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il63 [147K]
3 years ago
15

Pl help it’s for a grade I will give you Brainly if right

Mathematics
1 answer:
raketka [301]3 years ago
7 0

Answer:

2/4

Step-by-step explanation:

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How would you locate the point (-3, +7) on a coordinate grid? start at origin
Ivanshal [37]
To the right is postive so negive numbers with be on the left  and 7 will be above 0 so locate 3 backwards from 0 and go up 7
8 0
3 years ago
A person's height is 5-ft 3-in. Their shadow has a length of 3-ft 6-in. If a nearby tree has a shadow of length 10-ft 4-in, what
Alchen [17]

Answer: The height of tree = 15 ft. 6 inches

Step-by-step explanation:

Given: A person's height is 5-ft 3-in = [5 x (12 )+3 ]  inches    [ 1 ft= 12 inches]

= 63 inches      

Their shadow has a length of 3-ft 6-in = [3 x 12+6] inches    

= 42 inches

If a nearby tree has a shadow of length 10-ft 4-in = [10 x 12+4] inches

= 124 inches.

At the same time,

\dfrac{\text{Height of tree}}{\text{Height of person}}=\dfrac{\text{Length person's shadow}}{\text{Length of tree's shadow}}\\\\\dfrac{\text{Height of tree}}{63}=\dfrac{124}{42}\\\\\Rightarrow\ \text{Height of tree}=\dfrac{124}{42}\times63=186\ inches\\\\=\dfrac{186}{12}= 15.5 ft\ or\ 15 ft.\ 6\ inches.

Hence, the height of tree = 15 ft. 6 inches

7 0
3 years ago
you can speed from 0 to 25 m/s in 25 seconds and your friend can speed up from 0 to 6 m/s in 6 seconds. who is faster
aksik [14]

Answer:

Neither; see below

Step-by-step explanation:

Your acceleration: a=\frac{\Delta v}{\Delta t}=\frac{25-0}{25}=1m/s^2

Your friend's acceleration: a=\frac{\Delta v}{\Delta t}=\frac{6-0}{6}=1m/s^2

Therefore, since both you and your friend accelerate at the same rate, neither is faster.

7 0
2 years ago
Graph the numbers that are solutions to both inequalities below.
aleksklad [387]

Answer:

3x>12 2x/3 ≤ 6

3x>12, x =    4      2x/3, x =   2   ≤  6

3 0
3 years ago
There are some caps in a box. 1/6 of them are red, 1/3 are blue, and 3/7 of the remainder are green. If there are 27 green caps,
3241004551 [841]
\frac{1}{6}x+\frac{1}{3}x+\frac{3}{7}(x-(\frac{1}{6}x+\frac{1}{3}x))=x\\\frac{3}{7}(x-(\frac{1}{6}x+\frac{1}{3}x))=27\\\frac{3}{7}(x-(\frac{1}{2}x))=27\\\frac{3}{7}(\frac{1}{2}x)=27\\x=126

126 caps
5 0
3 years ago
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