Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
No she will not have enough paper because 200 times five is 1000 and if you multiply 23 by 52 is 1196 but I am not fully sure if this answer is right
Answer:
see explanation
Step-by-step explanation:
Under a translation < 5, - 9 >
5 is added to the original x- coordinate and 9 is subtracted from the original y- coordinate, that is
A(1, 4 ) → A'(1 + 5, 4 - 9 ) → A'(6, - 5 )
B(2, - 2 ) → B'(2 + 5, - 2 - 9 ) → B'(7, - 11 )
C(- 3, 2 ) → C'(- 3 + 5, 2 - 9 ) → C'(2, - 7 )
X would equal 70°.
For every triangle, all interior angles add up to 180°. This means that we can add together 42 and 68 to get 110°. Because the sum of all interior angles in a triangle must be 180°, we subtract 110 from 180 to see how much more we need, which gets us 70°.
I hope this helps!
10/25 = 2/5
Divide by 5 to get simplest form
