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EleoNora [17]
3 years ago
13

When you encounter a part of a lesson or a math problem that makes you feel stuck or confused, what do you do? How do you help y

ourself get unstuck and back on track?
could u guys plz give me some ideas on what makes u feel stuck or confused? i already now what to do when i ned help.
Mathematics
2 answers:
In-s [12.5K]3 years ago
8 0
When i get stuck and confused on a problem, i usually ask a family member or a friend. if they don’t know, then i do the rest of my work and ask my teacher for help
11Alexandr11 [23.1K]3 years ago
4 0

Answer:

well when ever i feel stuck i just skip it and come back to it , one thing that makes me feel stuck is doing algebra

Step-by-step explanation:

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How much for 1lb
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3 years ago
Graph the function f(x) = x3 – 5x2 + 6x using the graphing calculator. What are the solutions to the related equation? Check all
Juli2301 [7.4K]

the solutions to the related equation are 0,2,3 .

<u>Step-by-step explanation:</u>

Here we have , function  f(x) = x3 – 5x2 + 6x . Graph of this function is given below  . We need to find What are the solutions to the related equation . Let's find out:

Solution of graph means the  value of x at which the value of f(x) or function is zero . We can determine this by seeing the graph as at what value of x does the graph intersect or cut x-axis !

At x = 0 .

From the graph , at x=0 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 0^3- 5(0)^2 + 6(0)

⇒ f(0) =0

At x = 2 .

From the graph , at x=2 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 2^3- 5(2)^2 + 6(2)

⇒ f(0) =0

At x=3 .

From the graph , at x=3 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 3^3- 5(3)^2 + 6(3)

⇒ f(0) =0

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3 0
3 years ago
What is 8 7/9 − 3 2/3 =
maks197457 [2]

[|] Answer [|]

\boxed{5 \ 1/9}

[|] Explanation [|]

Rewrite the equation with parts separated:

8 + 7/9 - 3 - 2/3

Solve the whole number parts:

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Solve the fraction parts:

7/9 - 2/3

Find LCD of 7/9 & 2/3

7/9 - 6/9 = 1/9

5 + 1/9 = 5 1/9

\boxed{[|] \ Eclipsed \ [|]}

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