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3 years ago

Find measure of <_B.

Mathematics

1 answer:

kow [346]3 years ago

3 0

Firstly, we need to find m<BCA

<BCA+<BCD=180°

m<BCD=111°

<BCA+111°=180°

m<BCA=69°

Secondly, we need to find y

The sum of all angles of triangle is equal to 180°, so

$4y + 3y + 6 + 69 = 180 \\ 7y = 105 \\ y = 15$

Now we can find m<B

m<B=(3y+6)°

y=15

m<B=3×15+6=51°

Answer: m<B=51°

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Using our midpoint and endpoint, we have:
$(6, -11) = (\frac{11+x_2}{2}, \frac{-5+y_2}{2})
\\
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For the first equation (to find the x-coordinate) we will multiply both sides by 2:
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For the second equation (the y-coordinate) we multiply both sides by 2:
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\\
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Add 5 to both sides:
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This means that (x₂, y₂) is at (1, -17).

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