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Answer:
1) f⁻¹(x) = 6 ± 2√(x -1)
3) y = (x +4)² -2
5) y = (x -4)³ -4
Step-by-step explanation:
In general, swap x and y, then solve for y. Quadratics, as in the first problem, do not have an inverse function: the inverse relation is double-valued, unless the domain is restricted. Here, we're just going to consider these to be "solve for ..." problems, without too much concern for domain or range.
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1) x = f(y)
x = (1/4)(y -6)² +1
4(x -1) = (y-6)² . . . . . . subtract 1, multiply by 4
±2√(x -1) = y -6 . . . . square root
y = 6 ± 2√(x -1) . . . . inverse relation
f⁻¹(x) = 6 ± 2√(x -1) . . . . in functional form
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3) x = √(y +2) -4
x +4 = √(y +2) . . . . add 4
(x +4)² = y +2 . . . . square both sides
y = (x +4)² -2 . . . . . subtract 2
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5) x = ∛(y +4) +4
x -4 = ∛(y +4) . . . . . subtract 4
(x -4)³ = y +4 . . . . . cube both sides
y = (x -4)³ -4 . . . . . . subtract 4
Answer:
Pt. A: 25 cookies. Pt. B. $10.00
Step-by-step explanation:
1st you need to divide 10 cookies and $2 dollars, so 10/2= 5 cookies. So, it would be 5 cookies per dollar. So, then you would multiply 5 cookies*5 dollars, that equals 25. you would get 25 cookies for $5.00.
So, for Part B, you would divide 50 cookies by $5 dollars, and that would equal $10.00.
Hope this helped you!!! (:
Answer:
a. True. Rational numbers are closed under the sum operation, therefore, the sum of two rational numbers is always a rational number.
b. True. irrational numbers are closed under the sum operation, therefore, the sum of two irrationals numbers is always a irrational number.
c. True. The square of a real number is always a number greater than zero, and the sum of two numbers greater than zero is greater than zero.
d. True. The real numbers are closed under the product operation, then if a and b are reals numbers, the product ab is also a real number.
Step-by-step explanation:
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