Answer: -5x^3 -13x^2 -6x + 15ix + 39ix + 18i
Step-by-step explanation:
An equation with zeros at these numbers could be put in form x = number.
So, (x-3) could be set to 0 to get x=3.
So, you can look at these "answers" they give you and work backward to get:
(x-3)(x+2/5)(x-3i)
Multiply first two together.
x^2+2/5x-3x-6/5
simplify
x^2 - 2 3/5x -6/5
Change first term to have same denominator by multiplying by "1" in the form of -5/-5
-5x^2/-5 - 13/5x -6/5
Divide all terms by 1/5 (which is the same as multiplying each term by 5)
(-5x^2 -13x -6)
Now multiply by (x-3i)
-5x^3 -13x^2 -6x + 15ix + 39ix + 18i
4 sweets cost 28p altogether
28÷4=7p for each sweet
If each sweet costs 7p, then 7 sweets would be multiplied by 7
7×7p=49p
7 sweets cost 49p
First, you will have to convert both the fractions to improper fractions, then you will multiply both the fractions. Once you are done multiplying it you will convert them to mixed fractions.
Answer:
(x - 1) • (x - 2)
Step-by-step explanation:
Hope this helps!
