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Lelu [443]
3 years ago
13

What is 4/3s-3≥5-4 please help :).

Mathematics
1 answer:
saveliy_v [14]3 years ago
5 0

Let's solve your inequality step-by-step.

\frac{4}{3}s−3≥5−4

Step 1: Simplify both sides of the inequality.

\frac{4}{3}s−3≥1

Step 2: Add 3 to both sides.

\frac{4}{3}s−3+3≥1+3

\frac{4}{3}s≥4

Step 3: Multiply both sides by 3/4.

(\frac{3}{4})*(\frac{4}{3}s)≥(\frac{3}{4})*(4)


Answer: s≥3

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Need this asap, thanks in advance :)
sveticcg [70]

Answer:

non linear

Step-by-step explanation:

8 0
3 years ago
M is the midpoint of AN, A has coordinates (-6, -6) and M has coordinates (1, 2). Find the coordinates of N.
Cloud [144]
The midpoint, M, of points A and N is (8,10) because;
Point A is (-6,-6) which has a slope of 8/7 (rise/run) with M, (1,2). So, if 8/7 is repeated/ added to M, it will be point N.
1+7=8 (run/x)
2+8=10 (rise/y)
Put x and y together to get (8,10).
N= (8,10).
5 0
3 years ago
The diagram below represents the net of a triangular prism. What is the surface area of the triangular prism?
AleksandrR [38]

Answer:

(C)

Step-by-step explanation:

The diagram is divided ninto 5 parts that is rectangles ABCD, CHGD, GFEH and  triangles CIH and DGJ.

Area of rectangle ABCD= l{\times}b

=12{\times}6=72cm^{2}

Area rectangle CDHG=  l{\times}b

=12{\times}8=96cm^{2}

Area rectangle HGFE= l{\times}b

=10{\times}12=120cm^{2}

Area of triangles CIH and DIG= 2{\times}\frac{1}{2}{\times}b{\times}h

=6{\times}8=48cm^{2}

Surface area of the triangular prism=Area of rectangle ABCD+Area rectangle CDHG+Area rectangle HGFE+Area of triangles CIH and DIG

=72+96+120+48=336cm^{2}

Hence, option C is correct.

3 0
3 years ago
How many solutions does
Nikolay [14]

Answer:

A no solution

Step-by-step explanation:

y = 2x + 10

3y - 6x = 30

3(2x+10) -6x =30

6x +30 -6x =30

6x -6x = 30-30

0=0

3 0
3 years ago
PLEASE HELP QUICK!!!
GrogVix [38]
The answer is 50pi.
8 0
3 years ago
Read 2 more answers
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