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tester [92]
3 years ago
9

Can someone please help me i will mark brainliest

Mathematics
2 answers:
docker41 [41]3 years ago
6 0
Slope=7/2=3.5
Up 7, over 2
alekssr [168]3 years ago
6 0
Slope = 7/5 = 3.5
Up 7, over 2
That’s should be your answer
Hopefully I’m right :)
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I need the domain range and function. With an explanation
erastovalidia [21]
<h3>Answers:</h3>

Problem 1

  • Domain = -3 < x \le 3, interval notation (-3, 3]
  • Range = -3 \le y < 3, interval notation [-3, 3)
  • Is it a function? Yes

Problem 2

  • Domain = x \ge -2, interval notation [-2, \infty)
  • Range = All real numbers, interval notation (-\infty, \infty)
  • Is it a function? No

Problem 3

  • Domain = -4 \le x < 3, interval notation [-4, 3)
  • Range = -4 < y \le 3, interval notation (-4, 3]
  • Is it a function? Yes

Problem 4

  • Domain = All real numbers, interval notation (-\infty, \infty)
  • Range = y \le 4, interval notation (-\infty, 4]
  • Is it a function? Yes

==================================================

Explanations:

  1. The left most point is when x = -3, and we are not including this value due to the open hole. The other endpoint is included because it is a filled in circle. The domain is therefore -3 < x \le 3 which in interval notation is (-3, 3]. We have the curved parenthesis meaning "exclude endpoint" and the square bracket says "include endpoint". The range is a similar story but we're looking at the smallest and largest y values. Though be careful about which endpoint is open/closed. We have a function because it passes the vertical line test.
  2. The smallest x value is x = -2. There is no largest x value because the arrows say to go on forever to the right. We can say the domain is x \ge -2 which in interval notation is [-2, \infty). The range is (-\infty, \infty) to indicate "all real numbers". This graph fails the vertical line test, so it is not a function. The vertical line test is where we check to see if we can pass a vertical line through more than one point on the curve. In this case, such a thing is possible which is why it fails the test.
  3. This is the same idea as problem 1, though note the endpoints are flipped in terms of which has an open circle and which doesn't. It is not possible to draw a single vertical line to have it pass through more than one point on the curve, so it passes the vertical line test and we have a function.
  4. This is a function because it passes the vertical line test. The domain is the set of all real numbers due to the arrows in both directions. Any x value is a possible input. The range is y \le 4 which is the same as saying (-\infty, 4] in interval notation. This is because y = 4 is the largest y value possible. There is no smallest y value due to the arrows.

7 0
4 years ago
Ill Mark Brainliest If you answer Divide 1/2 and 1/8 and express the answer in simplest terms. If necessary, use / for the fract
Yuri [45]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
1/(x+4)(x-2)(x-5) excluded values
UNO [17]

Answer:

see explanation

Step-by-step explanation:

The excluded values are any values of x that make the function undefined

Given

\frac{1}{(x+4)(x-2)(x-5)}

The denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the values that x cannot be.

(x + 4)(x - 2)(x - 5) = 0

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

x - 2 = 0 ⇒ x = 2

x - 5 = 0 ⇒ x = 5

x = - 4, x = 2, x = 5 are the excluded values

4 0
3 years ago
Rihanna thinks that if a=b and c=d, then a+c=b+d. Is she correct
kap26 [50]

Answer:

yes. that logic works.

8 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE HELP ME OUT ILL GIVE YOU EXTRA POINTS
kati45 [8]

Answer: dont know just search it up

4 0
2 years ago
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