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3 years ago

HELP

Mathematics

2 answers:

mr Goodwill [35]3 years ago

6 0

<h2>9:4 (BEST ANSWER)</h2><h2>OR</h2><h2>9/4</h2><h2>OR</h2><h2>4.5:2</h2>

xeze [42]3 years ago

5 0

Answer:

Step-by-step explanation:

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PLS HELP ILL GIVE BRAINLIEST

inysia [295]

<h3>Answer: 14x - 8</h3>

=======================================================

Explanation:

I'll use the quadratic formula to find the roots or x intercepts. This slight detour allows us to factor without having to use guess-and-check methods.

The equation is of the form ax^2+bx+c = 0

a = 12
b = -11
c = -5

This leads to...

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-11)\pm\sqrt{(-11)^2-4(12)(-5)}}{2(12)}\\\\x = \frac{11\pm\sqrt{361}}{24}\\\\x = \frac{11\pm19}{24}\\\\x = \frac{11+19}{24} \ \text{ or } \ x = \frac{11-19}{24}\\\\x = \frac{30}{24} \ \text{ or } \ x = \frac{-8}{24}\\\\x = \frac{5}{4} \ \text{ or } \ x = -\frac{1}{3}$

Now use those roots to form these steps

$x = \frac{5}{4} \ \text{ or } \ x = -\frac{1}{3}\\\\4x = 5 \ \text{ or } \ 3x = -1\\\\4x - 5 =0 \ \text{ or } \ 3x+1 = 0\\\\(4x-5)(3x+1) = 0$

Refer to the zero product property for more info.

Therefore, the original expression factors fully to (4x-5)(3x+1)

Use the FOIL rule to expand it out and you should get 12x^2-11x-5 again.

----------------------------------------------

We did that factoring so we could find the side lengths of the rectangle.

I'm using the fact that area = length*width

L = length = 4x-5
W = width = 3x+1

The order of length and width doesn't matter.

From here, we can then compute the perimeter of the rectangle

P = 2(L+W)

P = 2(4x-5+3x+1)

P = 2(7x-4)

P = 14x - 8

6 0

2 years ago

Pls help<br> Escape Question 2

elixir [45]

Answer:

unlock code is 11

A= 27

B=16

C=1

(11)^1 = 11

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A line contains the points R (-1, 8) S (1, 4) and T (6, y). Solve for y. Be sure to show and explain all work.

Nikitich [7]

Given:

A line contains the points R(-1, 8), S(1, 4) and T(6, y).

To find:

The value of y.

Solution:

Three points are collinear if:

$x_1(y_2-y_3)+x_2(y_3-y_2)+x_3(y_1-y_2)=0$

A line contains the points R(-1, 8), S(1, 4) and T(6, y). It means, these points are collinear.

$-1(4-y)+1(y-8)+6(8-4)=0$

$-4+y+y-8+48-24=0$

$2y+12=0$

Subtract 12 from both sides.

$2y=-12$

Divide both sides by 2.

$y=\dfrac{-12}{2}$

$y=-6$

Therefore, the value of y is -6.

3 0

2 years ago

Please help. Will mark Brainliest

mario62 [17]

First is B, since 1 and 3 are corresponding angles, they must be equal

Next is I, 3 and 5 must be equal since they are vertically opposite

Last is transitive property
Since 1 = 3 and 3 = 5, then 1 must equal 5

7 0

2 years ago

(x^2–x–4)multiplied by(x–5)

Sergio [31]

$(x-5)(x^2-x-4) =x^3-6x^2+x+20$