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Lelechka [254]
2 years ago
15

How long (to the next whole year) will it take

Mathematics
1 answer:
fomenos2 years ago
6 0

Step-by-step explanation:

2x = x1.2^n

2 = 1.2^n

log1.2(2) = n

log10(2)/log10(1.2) = n = 3.801784017...

so, rounded to the next whole year it takes 4 years.

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Find the value of q in the following system so that the solution to the system is(4,2) 3x-2y=8
Nataliya [291]
We have that
<span>3x-2y=8 -----> equation 1
2x+3y=Q----> equation 2

the solution is the point </span><span>(4,2)
in the equation 2 substitute the value of
x=4
y=2
so
</span>2x+3y=Q------> 2*4+3*2=Q-------> Q=8+6------> Q=14
<span>
the answer is
Q=14

</span>
3 0
3 years ago
Write y=2/3x +5 in standard form​
DochEvi [55]

Answer:

2x-3y=-15

Step-by-step explanation:

y=2/3x+5 and write in standard form.

and you come up with 2x-3y=-15.

6 0
2 years ago
What are the factors of 4 and 10?
zmey [24]
Factors of 4 : 1,2,4

factors of 10 : 1,2,5,10
8 0
2 years ago
Read 2 more answers
If PN=29cm and MN=13 , then PM=?
HACTEHA [7]

*see attachment for the figure referred to

Answer/Step-by-step explanation:

1. PN = 29

MN = 13

PM = ?

PN = PM + MN (Segment addition postulate)

PN - MN = PM (subtract MN from each side)

29 - 13 = PM (substitute)

16 = PM

PM = 16 cm

2. PN = 34, MN = 19, PM = ?

PN = PM + MN (sediment addition postulate)

PN - MN = PM (subtract MN from each side)

34 - 19 = PM (substitute)

15 = PM

PM = 15 cm

3. PM = 19, MN = 23, PN = ?

PN = PM + MN (Segment addition postulate)

PN = 19 + 23 (substitute)

PN = 42 cm

4. MN = 82, PN = 105, PM = ?

PN = PM + MN (segment addition postulate)

PN - MN = PM (subtract MN from each side)

105 - 82 = PM (substitute)

23 = PM

PM = 23 cm

5. PM = 100, MN = 100, PN = ?

PN = PM + MN (Segment addition postulate)

PN = 100 + 100 (substitute)

PN = 200 cm

7 0
3 years ago
Sin (x/2)= √2- sin (x/2) solve for the exact solutions in the interval (0, 2π)
serg [7]

sin\left( \frac{x}{2} \right)=\sqrt{2}-sin\left( \frac{x}{2} \right)\implies sin\left( \frac{x}{2} \right)+sin\left( \frac{x}{2} \right)=\sqrt{2}\implies 2sin\left( \frac{x}{2} \right)=\sqrt{2} \\\\\\ sin\left( \cfrac{x}{2} \right)=\cfrac{\sqrt{2}}{2}\implies sin^{-1}\left[ sin\left( \cfrac{x}{2} \right) \right]=sin^{-1}\left( \cfrac{\sqrt{2}}{2} \right) \implies \cfrac{x}{2}= \begin{cases} \frac{\pi }{4}\\\\ \frac{3\pi }{4} \end{cases} \\\\[-0.35em] ~\dotfill

\cfrac{x}{2}=\cfrac{\pi }{4}\implies \boxed{x=\cfrac{\pi }{2}}~\hfill \cfrac{x}{2}=\cfrac{3\pi }{4}\implies \boxed{x=\cfrac{3\pi }{2}}

5 0
2 years ago
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