We have that
<span>3x-2y=8 -----> equation 1
2x+3y=Q----> equation 2
the solution is the point </span><span>(4,2)
in the equation 2 substitute the value of
x=4
y=2
so
</span>2x+3y=Q------> 2*4+3*2=Q-------> Q=8+6------> Q=14
<span>
the answer is
Q=14
</span>
Answer:
2x-3y=-15
Step-by-step explanation:
y=2/3x+5 and write in standard form.
and you come up with 2x-3y=-15.
Factors of 4 : 1,2,4
factors of 10 : 1,2,5,10
*see attachment for the figure referred to
Answer/Step-by-step explanation:
1. PN = 29
MN = 13
PM = ?
(Segment addition postulate)
(subtract MN from each side)
(substitute)


2. PN = 34, MN = 19, PM = ?
(sediment addition postulate)
(subtract MN from each side)
(substitute)


3. PM = 19, MN = 23, PN = ?
(Segment addition postulate)
(substitute)

4. MN = 82, PN = 105, PM = ?
(segment addition postulate)
(subtract MN from each side)
(substitute)


5. PM = 100, MN = 100, PN = ?
(Segment addition postulate)
(substitute)
