4, 8, 10, 7, 3, 4... Those r in order from top to bottom! it's all about the simplification!
Answer:
A = 100
B = 50
C = 30
Step-by-step explanation:
You can make this equation to solve:
2x+x+x-20=180
4x-20=180
+20 +20
4x=200
divide both sides by 4
200/4 = 50
x=50, B = x = 50
2x = 100 = A
x-20 = 30 = C
Given:
Total number of calculators in a box = 10
Defective calculators in the box = 1
To find:
The number of ways in which four calculators be selected and one of the four calculator is defective.
Solution:
We have,
Total calculators = 10
Defective calculators = 1
Then, Non-defective calculator = 10-1 = 9
Out of 4 selected calculators 1 should be defective. So, 3 calculators are selected from 9 non-defective calculators and 1 is selected from the defective calculator.






Therefore, the four calculators can be selected in 84 ways.
I think that the area is 54 I am not sure I haven’t done math like this in a long time