How many sides does a regular polygon have if each of its interior angles is 140 degrees?

Mathematics

2 answers:

morpeh [17]3 years ago

8 0

I think the answer would be root

faltersainse [42]3 years ago

5 0

9 sides
Method 1: Since the interior angle 140 degrees, the supplement of this is the exterior angle and equal to 40 degrees. Hence the number of sides is 360/40 = 9 sides.

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Find the length of each missing side and each missing angle in the isosceles triangle below.

Zarrin [17]

Answer:

x = 45

y = 45

z = 11.1

Step-by-step explanation:

Remark

The triangle is a right triangle. That means that it has 1 right angle.

It is also isosceles which means that the two legs that are not the hypotenuse are equal.

Result: z and 11.1 are equal z = 11.1

More remark

If the triangle is isosceles, that means that the angles that are not right angles must also be equal.

90 + x + y = 180

but x = y

90 + 2x = 180 Subtract 90

2x = 180 - 90 Divide by 2

2x/2 = 90/2

x = 45

3 0

2 years ago

HELP PLEASE WILL MARK BRAINLIEST!!

Arte-miy333 [17]

Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

$from \: the \: figure \\ AB = 300 \: ft \: \: \: angle \: C = 60 \:( theta)\: degress \\ in \: triangle \: ABC \: using \: tan \: theta\\ \tan(60) = \frac{opposite \: side}{adjacent \: side} \\ \tan(60) = \frac{300}{BC} \\ \sqrt{3} = \frac{300}{BC} \\ BC = \frac{300}{ \sqrt{3} } \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\ \tan(30 ) =\frac{opposite \: side}{adjacent \: side} \\ \tan(30) = \frac{300}{BD} \\ \frac{1}{ \sqrt{ 3} } = \frac{300}{BD} \\ BD = 300 \sqrt{3} \\ CD = BD - BC \\ = 300 \sqrt{3 } - 100 \sqrt{3} \\ = (300 - 100) \sqrt{3} \\ = 200 \sqrt{3 } \\ = 200 \times 1.732 \\ = 346.4 \: ft$