All categories

2 years ago

Find the gradient of the line segment between the points (-2,3) and (0,2).

Mathematics

1 answer:

grandymaker [24]2 years ago

8 0

Answer:

kzz bjjijbsdbhi hipdssihhhsihpS

Step-by-step explanation:

EKEJJJBJ

You might be interested in

Solve the literal equation for x. <br><br> w=5+3(x−1)

ICE Princess25 [194]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

x = w/3 - 2/3

4 0

3 years ago

What is triangle angel sum theorem

Flauer [41]

The triangle angle sum theorem states that the 3 angles in the triangle must equal 180 degrees.

3 0

2 years ago

Pattie is itemizing deductions on her federal income tax return and had $4800

muminat

Answer: 1500

Step-by-step explanation:

6 0

2 years ago

Which of the I-values are solutions to both of the following inequalities?

lidiya [134]

Answer:

Option (C)

Step-by-step explanation:

Given inequalities are,

81 > x and x > 68

Therefore, 81 > x > 68 is the inequality representing the solution area for x.

Out of x = 88, 85 and 80,

x = 80 will lie between the range of x = 68 and x = 81.

Therefore, Option (C) will be the correct option.

5 0

2 years ago

Which expression is equivalent to StartFraction 2 a + 1 Over 10 a minus 5 Endfraction divided by StartFraction 10 a Over 4 a squ

const2013 [10]

Answer:

$\frac{(2a + 1)^2}{50a}$

Step-by-step explanation:

Given

$\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}$

Required

Find the equivalent

We start by changing the / to *

$\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}$

$\frac{2a + 1}{10a - 5} * \frac{4a^2 - 1}{10a}$

Factorize 10a - 5

$\frac{2a + 1}{5(2a - 1)} * \frac{4a^2 - 1}{10a}$

Expand 4a² - 1

$\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1}{10a}$

$\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1^2}{10a}$

Express (2a)² - 1² as a difference of two squares

Difference of two squares is such that: $a^2- b^2= (a+b)(a-b)$

The expression becomes

$\frac{2a + 1}{5(2a - 1)} * \frac{(2a - 1)(2a + 1)}{10a}$

Combine both fractions to form a single fraction

$\frac{(2a + 1)(2a - 1)(2a + 1)}{5(2a - 1)10a}$

Divide the numerator and denominator by 2a - 1

$\frac{(2a + 1)((2a + 1)}{5*10a}$

Simplify the numerator

$\frac{(2a + 1)^2}{5*10a}$

$\frac{(2a + 1)^2}{50a}$

Hence,

$\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}$ = $\frac{(2a + 1)^2}{50a}$

4 0

3 years ago