Answer:
2.306
Step-by-step explanation:
u while times the number
Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: number of daily text messages a high school girl sends.
This variable has a population standard deviation of 20 text messages.
A sample of 50 high school girls is taken.
The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:
X[bar]≈N(μ;δ²/n)
This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:
Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)
a.
P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836
b.
P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)
P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328
I hope you have a SUPER day!
Answer:
x+y=10 which means that x=10-y
Replace 10-y in the other equation which gives you:
10-y-y=6
10-2y=6
-2y=-4
y=2
Replace 2 in any of the 2 equations same answer for both:
x+y=10
x+2=10
x=8
So,
=512-8
=504
Hope this helps!
Answer:
We are given the below data:
Sample Number Sample Mean
1 11.8
2 12.5
3 15.1
4 14.3
5 13.0
6 12.9
7 10.2
8 11.5
9 12.9
10 15.4
Now the most likely mean of the population can be found by finding the mean of given sample means. It is given below:
Therefore, the most likely mean of the population from which the samples were taken is 12.96
Answer:
a. 49
b. 1
c. x^2+10x+25
Step-by-step explanation:
Symply substitute the values (5, -3, x+3) in the equation (x+2)^2
