I need help with my math work the problem is on a screen shot
2 answers:
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Answer:
The coefficient of variation for the systolic measurements is 12.8 %
The coefficient of variation for the diastolic measurements is 16.3 %
Therefore, we can conclude that the systolic measurements are less dispersed as compared to diastolic measurements.
Step-by-step explanation:
The coefficient of variation is the ratio of standard deviation of the data to the mean of the data. It shows the dispersion in the data set.
Coefficient of variation for the systolic measurements:
Mean = μ = (120 + 128 + 156 + 98 + 154 + 122 + 118 + 136 + 128 + 120)/10
Mean = μ = 1280/10
Mean = μ = 128
Standard deviation = σ =
Using excel the standard deviation is found to be
Standard deviation = σ = 16.4
Coefficient of variation = σ/μ
Coefficient of variation = 16.4/128
Coefficient of variation = 0.128
Coefficient of variation = 12.8%
Coefficient of variation for the Diastolic measurements:
Mean = μ = (79 + 76 + 75 + 51 + 92 + 87 + 59 + 64 + 72 + 81)/10
Mean = μ = 736/10
Mean = μ = 73.6
Standard deviation = σ =
Using excel the standard deviation is found to be
Standard deviation = σ = 12
Coefficient of variation = σ/μ
Coefficient of variation = 12/73.6
Coefficient of variation = 0.163
Coefficient of variation = 16.3%
Conclusion:
We can conclude that the systolic measurements (12.8%) are less dispersed as compared to diastolic measurements (16.3%).
Why are you still asking these? Just add up the exponents!
