Answer:
4.415 g of FeSO₄
Explanation:
The balance chemical equation for given single replacement reaction is as follow;
Fe + H₂SO₄ → FeSO₄ + H₂
Data Given;
Volume = 650 mL = 0.65 L
Density at STP = 0.08988 g/L
Mass = Density × Volume = 0.08988 g/L × 0.65 L = 0.0584 g
Step 1: <u>Calculate Moles of H₂ as; </u>
Moles = Mass / M.Mass
Moles = 0.0584 g / 2.01 g/mol
Moles = 0.0290 mol of H₂
Step 2: <u>Find out moles of FeSO₄ as;</u>
According to balance chemical equation,
1 mole of H₂ is produced along with = 1 mole of FeSO₄
So,
0.0290 moles of H₂ will be produced along with = X moles of FeSO₄
Solving for X,
X = 0.0290 × 1 mol / 1 mol
X = 0.0290 moles of FeSO₄
Step 3: <u>Calculate mass of FeSO₄ as;</u>
Mass = Moles × M.Mass
Mass = 0.0290 mol × 151.90 g/mol
Mass = 4.415 g of FeSO₄
Answer:
1-Ethyl-3-methylidenecyclopentane
Step-by-step explanation:
Formula = C₈H₁₄. An alkane has formula C₈H₁₈. ∴ X contains 2 double bonds, 2 rings, or 1 ring and 1 double bond.
X absorbs only 1 mol of hydrogen. ∴ X contains 1 ring and 1 double bond.
Hydrogenation gives 1-ethyl-3-methylcyclopentane.
Ozonolysis gives formaldehyde, so X must contain a =CH₂ group.
Hydrogenation of X converted the =CH₂ to -CH₃.
X is 1-ethyl-3-methylidenecyclopentane.
You can see the reactions in the image below.
Answer is: <span>B) -50.2 kJ.
Balanced chemical reaction: </span>N₂(g) + 3H₂(g) → 2NH₃(g) ΔH = -<span>100.4 kJ.
This is exothermic reaction, because heat is released and energy is include as product of chemical reaction.
Make proportion, two moles of ammonia released 100.4 kJ of heat, then one mole of ammonia released:
2 mol(NH</span>₃) : (-100.4 kJ) = 1 mol : ΔH.
ΔH = -50.2 kJ; <span>heat released per mole of NH</span>₃.
Grease and non-polar too, so the <span>tetrachloroethylene would be a solvent.</span>
Answer:
It's explained by nebular theory, which describes the forces and processes at play as a nebula spins and accretes into a star and its planets orbiting it. A key piece of information to always keep in mind is that the force of gravity is responsible for accretion and all the objects it forms.
Explanation:
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