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tino4ka555 [31]
3 years ago
6

50 grams of acetic acid C2H4O2 are dissolved in 200 g of water. Calculate the weight % and mole fraction of the acetic acid in t

he solution
Chemistry
1 answer:
Len [333]3 years ago
6 0
50g   of   C_2H_4O_2   in   200g    H_2O

so:

\frac{50}{200+50}+100\%= \frac{50*100}{250}\%=20\%

MW of acid = 2*C+4*H+2*O = 2*12+4*1+2*16=

=24+4+32=60g/mol

so:

\frac{50g}{60g/mol}\approx0.83moles

it means that

in 50g of acid there is \approx0.83moles of acid

MW of H_2O = 2*H+O=2*1+16=2+16=18g/mol

so:

\frac{200g}{18g/mol}\approx11.11moles

it means that:

in 200g of water there is \approx11.11moles of water

therefore:

\frac{0.83mol}{11.11mol+0.83mol}= \frac{0.83mol}{11.94mol}=0.069

So your answers are:

20\%

and the mole fraction is:

0.069
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