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julia-pushkina [17]
3 years ago
11

What is the common ratio for the geometric sequence? 32, 8, 2, 12, ... Enter your answer in the box.

Mathematics
1 answer:
mamaluj [8]3 years ago
3 0

Answer:

Given sequence is not a geometric progression and there will be no common ration for this sequence.

Step-by-step explanation:

Need to determine common ration for the following geometric sequence

32, 8, 2, 12, ...

In given geometric sequence  

a1 = 32, a2=8, a3=2, a4=12 ……….

Common ratio = \frac{a_2}{a_1} =\frac{a_3}{a_2} =\frac{a_4}{a_3}

\frac{a_2}{a_1}=\frac{8}{32}=\frac{1}{4}

\frac{a_3}{a_2} =\frac{2}{8}=\frac{1}{4}

\frac{a_4}{a_3}=\frac{12}{2}=6

Since \frac{a_2}{a_1}=\frac{a_3}{a_2}\neq\frac{a_4}{a_3}  so we can say that given sequence is not a geometric progression and there will no no common ration for this sequence.

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After staring at this for a few seconds, I think the equation

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is asking you to simplify the left hand side so that it has a form matching the right hand side, and [1] and [2] are placeholders. My guess is that they're supposed to be integers.

Notice that

\sqrt{10}=\sqrt{5\cdot2}=\sqrt5\cdot\sqrt2

\sqrt{15}=\sqrt{5\cdot3}=\sqrt5\cdot\sqrt3

\implies\sqrt{10}\cdot\sqrt{15}=(\sqrt5)^2\cdot\sqrt2\cdot\sqrt3=5\sqrt{2\cdot3}=5\sqrt6

Then multiplying by -5, we have

-5\sqrt{10}\cdot\sqrt{15}=-25\sqrt6

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Step-by-step explanation:

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Step-by-step explanation:

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A sample of a radioactive substance decayed to 97% of its original amount after a year. (Round your answers to two decimal place
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Answer:

a) The half life of the substance is 22.76 years.

b) 5.34 years for the sample to decay to 85% of its original amount

Step-by-step explanation:

The amount of the radioactive substance after t years is modeled by the following equation:

P(t) = P(0)(1-r)^{t}

In which P(0) is the initial amount and r is the decay rate.

A sample of a radioactive substance decayed to 97% of its original amount after a year.

This means that:

P(1) = 0.97P(0)

Then

P(t) = P(0)(1-r)^{t}

0.97P(0) = P(0)(1-r)^{0}

1 - r = 0.97

So

P(t) = P(0)(0.97t)^{t}

(a) What is the half-life of the substance?

This is t for which P(t) = 0.5P(0). So

P(t) = P(0)(0.97t)^{t}

0.5P(0) = P(0)(0.97t)^{t}

(0.97)^{t} = 0.5

\log{(0.97)^{t}} = \log{0.5}

t\log{0.97} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.97}}

t = 22.76

The half life of the substance is 22.76 years.

(b) How long would it take the sample to decay to 85% of its original amount?

This is t for which P(t) = 0.85P(0). So

P(t) = P(0)(0.97t)^{t}

0.85P(0) = P(0)(0.97t)^{t}

(0.97)^{t} = 0.85

\log{(0.97)^{t}} = \log{0.85}

t\log{0.97} = \log{0.85}

t = \frac{\log{0.85}}{\log{0.97}}

t = 5.34

5.34 years for the sample to decay to 85% of its original amount

8 0
3 years ago
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