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jeka57 [31]
3 years ago
10

Show steps in solving ax^2+bx+c=0

Mathematics
1 answer:
Helen [10]3 years ago
6 0
Solving for A.

STEP 1 ● Add -bx to both sides.
ax^2 + bx + c + -bx = 0 + -bx
ax^2 + c = -bx

STEP 2 ● Add -c to both sides.
ax^2 + c + -c = -bx + -c
ax^2 = -bx -c

STEP 3 ● Divide both sides by x^2
ax^2 / x^2 = -bx -c / x^2
a = -bx -c / x^2

ANSWER ● a = -bx -c / x^2

Hope I helped
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<h3>The equation of a circle.</h3>

Mathematically, the general form of the equation of a circle is given by;

(x - h)² + (y - k)² = r²

<u>Where:</u>

  • h and k represents the coordinates at the center.
  • r is the radius of a circle.

Based on the information provided that the center of the circle lies on the y-axis, we have:

(h, k) = (0, 4)

Radius, r = 3 units.

Substituting the given parameters into the formula, we have;

(x - 0)² + (y - 4)² = 3²

x ² + y² - 8y + 16 = 9

x ² + y² - 8y + 7 = 0.

Therefore, the set of values which might correspond to the circle are A = 1, B = 1, C = 0, D = -8 and E = 7.

Read more on circle here: brainly.com/question/1615837

#SPJ1

<u>Complete Question:</u>

The general form of the equation of a circle is Ax² + By² + Cx + Dy + E = 0, where A = B. If the circle has a radius of 3 units and the center at (0, 4), which set of values of A, B, C, D, and E correspond to the circle?

4 0
2 years ago
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