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3 years ago

A friend gives you 120 feet of fencing. You want to make a circular dog

Mathematics

1 answer:

solong [7]3 years ago

4 0

Answer:

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Identify the variables in the graph describe how the variables are related

Alex17521 [72]

The time(h), would be the independent variable and the temperature(C) would be the dependent variable.

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4 years ago

What two decimal are between the square root of 62

viva [34]

7 and 8 because the square root is 7.874

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2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

IRISSAK [1]

1. √169 = √(13 · 13) = 13

2. √169 = √(13 · 13) = 13

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3 years ago

A Square has a length of 9 feet. Find the area and perimeter.

prohojiy [21]

A square is the same length on each side so each side would be 9

9+9+9+9= 36ft (perimeter)

Again each side if 9 feet to find the area u just multiply the length and width here the length and width are the same (9)

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3 years ago

Mr. Good Wrench advertises that a customer will have to wait no more than 30 minutes for an oil change. A sample of 26 oil chang

Andru [333]

Answer:

The 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

Step-by-step explanation:

The (1 - α)% confidence interval for the population standard deviation is:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

The information provided is:

n = 26

s = 4.8 minutes

Confidence level = 90%

Compute the critical values of Chi-square as follows:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.10/2, (26-1)}=\chi^{2}_{0.05, 25}=37.652$

$\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.10/2, (26-1)}=\chi^{2}_{0.95, 25}=14.611$

*Use a Chi-square table.

Compute the 90% confidence interval for the population standard deviation waiting time for an oil change as follows:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

$=\sqrt{\frac{(26-1)\times 4.8^{2}}{37.652}}\leq \sigma\leq \sqrt{\frac{(26-1)\times 4.8^{2}}{14.611}}\\\\=3.9113\leq \sigma\leq 6.2787\\\\\approx 3.9 \leq \sigma\leq6.3$

Thus, the 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

3 0

3 years ago