Remember
we can do anything to an equation as long as we do it to both sides
try to isolate the variable
you have 2 types
x+b=c
x/b=c
fior the first type, minus b from both sides to get
x=c-b
for the second, multiply both sides by b to get rid of the fraction to get
x=cb
also remember that -x times -1=x
b.add 25 to both sides
-a=20
multiply -1
a=-20
c.
-t/8=-4
multiply both sides by 8
-t=-32
mutiply -1
t=32
d. -n/-5=-30
mulitply both sides by -5
-n=150
multiply both sides by -1
n=-150
e. multiply both sides by 12
-l=144
multiply b y-1
l=-144
Answer:
<h2>b = 15°</h2>
Step-by-step explanation:
If Pq = RQ then ΔPQR is the isosceles triangle. The angles QPR and PRQ have the same measures.
We know: The sum of the measures of the angeles in the triangle is equal 180°. Therefore we have the equation:
m∠QPR + m∠PRQ + m∠RQP = 180°
We have
m∠QPR = m∠PRQ and m∠RQP = 60°
Therefore
2(m∠QPR) + 60° = 180° <em>subtract 60° from both sides</em>
2(m∠QPR) = 120° <em>divide both sides by 2</em>
m∠QPR = 60° and m∠PRQ = 60°
Therefore ΔPRQ is equaliteral.
ΔPSR is isosceles. Therefore ∠SPR and ∠PRS are congruent. Therefore
m∠SPR = m∠PRS
In ΔAPS we have:
m∠SPR + m∠PRS + m∠RSP = 180°
2(m∠SPR) + 90° = 180° <em>subtract 90° from both sides</em>
2(m∠SPR) = 90° <em>divide both sides by 2</em>
m∠SPR = 45° and m∠PRS = 45°
m∠PRQ = m∠PRS + b
Susbtitute:
60° = 45° + b <em>subtract 45° from both sides</em>
15° = b
Answer:
Pretty sure it's B, the second one from the top
Yes in science it’s the scale factor of the division barns end. Dive o Ebro dodo ooo
Hey jm correct answer
