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3 years ago

Find the measures of 21 and 2

Mathematics

1 answer:

KatRina [158]3 years ago

6 0

Measure 1 would be 59 degrees (180-121)
Measure 2 would be 121 degrees (vertical angle theorem)

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A randomly generated list of integers from 0 to 4 is being used to simulate an event, with the numbers 1, 2, and 3 representing

Tresset [83]

Answer:

I think the anwser is

<h2>C.60 percent</h2>

hope it helped

6 0

3 years ago

Julie will build a rectangular pen for her dog against a barn. A wall from the barn will form one side of the pen. She has 32 m

MAXImum [283]

Answer:

<h3> The width (side perpedicular to the barn): <u>x = 8 m</u></h3><h3> The lenght (side parallel to the barn): <u>y = 16 m</u> </h3>

Step-by-step explanation:

x - the width of the barn

She has 32 m of fencing so for the lenght remain (32-2x) m of fencing:

y = 32 - 2x

Area of the fencing: A = x•y

A(x) = x•(32 - 2x)

A(x) = -2x² + 32x ← quadratic function

The maximum value of quadratic function occurs at: $x=-\frac b{2a}$

a = -2, b = 32

$x=-\frac b{2a}=-\frac{32}{2\cdot(-2)}=-(-8)=8$

32-2x = 32 - 2•8 = 16

4 0

3 years ago

let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a

tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) = y = 0(x) + 1(y)

Matrix Representation of $T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]$

now, eigen value of 'T'

$T - kI = \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]$

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

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6 0

1 year ago

1.8×10^-2-3.9×10^-3 what is the answer

Alja [10]

The answer is 0.0141

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3 years ago

Read 2 more answers

What does the slope of the line represent within the context of my graph

Nata [24]

The slope of the line is the velocity, or rate of change, of y with respect to x. In other terms, the slope tells you how much y will change for every change in x by one unit. For example if the slope, which is velocity, is 2. y will increase by two units every time x increases by one unit. Your graph is not pictured nor explained, so I cannot give you the specific context beyond the principle that the slope of a line is a constant velocity or rate of change.

7 0

3 years ago

Read 2 more answers