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OlgaM077 [116]
3 years ago
8

The cost of cloth is directly proportional to the length. A 3.2-metre length of cloth costs $38

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0

Answer:

x = \$28.5

Step-by-step explanation:

Given

Variation: Direct Proportion

3.2m = \$38

Required

Determine the cost of 2.4m length

Represent the cost of 2.4m length with x

So, we have:

3.2m = \$38

and

2.4m = x

Cross Multiply:

3.2m * x = \$38 * 2.4m

3.2 * x = \$38 * 2.4

Solve for x

x = \frac{\$38 * 2.4}{3.2}

x = \frac{\$91.2}{3.2}

x = \$28.5

<em>Hence, the cost of 2.4m length is $28.5</em>

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Y=x+3over 8 proportional or nonproportional
Inessa [10]

Answer:

nonproportional

Step-by-step explanation:

x + 3

------- is definitely nonproportional.  The reason for this is that the graph (a

   8                                                      straight line) does not pass through the                          

                                                            origin; it's offset by 3/8 unit up from the          

                                                             origin.

6 0
3 years ago
2/3 greater than or less than 1/5
UkoKoshka [18]
2/3 is greater. 1/5 is less.
4 0
3 years ago
Read 2 more answers
RS = 4x – 9, ST = 19, RT = 80 – 14<br><br> Equation:<br><br> 82 – 14<br><br> RS<br><br> RT
algol13

Step-by-step explanation:

The expressions are not properly written

Given

RS = 4x – 9

ST = 19

RT = 8x – 14

Based on the given parameters, the addition postulate below is true

RS+ST = RT

Substitute

4x-9+19 = 8x-14

collect like terms

4x-8x = -14-19+9

-4x = -33+9

-4x = -24

x = -24/-4

x = 6

Get RS:

RS = 4x-9

RS = 4(6)- 9

RS = 24-9

RS = 15

Get RT:

RT = 8x - 14

RT = 8(6)-14

RT = 48-14

RT = 34

4 0
3 years ago
Data consistent with summary quantities in the article "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among
Olegator [25]

Answer:

a) X[bar]₁=  1839.20 cal

b) X[bar]₂= 1779.07 cal

c) S₁= 386.35 cal

Step-by-step explanation:

Hello!

You have two independent samples,

Sample 1: n₁= 15 children that did not eat fast food.

Sample 2: n₂= 15 children that ate fast food.

The study variables are:

X₁: Calorie consumption of a kid that does not eat fast food in one day.

X₂: Calorie consumprion of a kid that eats fast food in one day.

a)

The point estimate of the population mean is the sample mean

X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal

b)

X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal

c)

To calculate the sample standard deiation, you have to calculate the sample variance first:

S₁²= \frac{1}{n_1-1}[∑X₁² - (( ∑X₁)²/n₁)]= \frac{1}{14} + [52829538 - (\frac{27588^{2} }{15}) = 149263.4571 cal²

S₁= 386.35 cal

I hope it helps!

7 0
3 years ago
I need help assap
Bad White [126]
It’s 2=x because you have start with 2 then 5
5 0
3 years ago
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