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Cerrena [4.2K]
3 years ago
8

2/3 greater than or less than 1/5

Mathematics
2 answers:
ivanzaharov [21]3 years ago
5 0
Greater. Imagine it as a pie you would rather 2 big slices of pie on a 3 slice pie, than 1 skinny slice on a 5 piece pie. 
UkoKoshka [18]3 years ago
4 0
2/3 is greater. 1/5 is less.
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Add<br> 6 3/5 + (-6 1/3<br> Enter your answer as a simplified fraction in the box
Sholpan [36]
Okay so basically the answer would be 4/15
8 0
2 years ago
Flora has 33 flowers and she can pick 7 flowers a minute. Write an equation that shows how many flowers, F, that Flora will have
monitta
F=7M
33=M
Both answers will work
3 0
3 years ago
louise bought 80 metres of fencing to make an enclosure for her pet dog .tommy if louise expects a rectangular enclosure what is
OleMash [197]

Answer:

400 m^2.

Step-by-step explanation:

The largest  area is obtained where the enclosure is a square.

I think that's the right answer because a square is a special form of a rectangle.

So the square would be 20 * 20  = 400 m^2.

Proof:

Let the  sides of the rectangle be x and y m long

The area A = xy.

Also the perimeter  2x + 2y = 80

x + y = 40

y = 40 - x.

So substituting for y in A = xy:-

A = x(40 - x)

A = 40x - x^2

For maximum value of A  we find the derivative and equate it to 0:

derivative A' =  40 - 2x = 0

2x = 40

x = 20.

So y = 40 - x

= 40 - 20

=20  

x and y are the same value so x = y.

Therefore for maximum area the rectangle is a square.

3 0
3 years ago
What’s the answer pls
MAXImum [283]
37.1
35 * .06 = 2.1
35 + 2.1 = 37.1
8 0
3 years ago
Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''
Nonamiya [84]

Answer:

a-e^x,e^{-x}

b-x^{-2}

c-x^3

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

D^2-1=0

(D-1)(D+1)=0

D=1,-1

Then , the solution of given differential equation

y=e^x,y=e^{-x}

2.7x^2y''+14xy'-14 y=0

Y=y=x^3

y=3x^2

y''=6x

Substitute in the given differential equation

42x^3+42x^3-14x^3\neq 0

Hence, x^3 is not a solution of given differential equation

e^x,e^{-x} are also not a solution of given differential equation.

y=x^{-2}

y'=-2x^{-3}

y''=6x^{-4}

Substitute the values in the differential equation

7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}

=42x^{-2}-28x^{-2}-14x^{-2}=0

Hence, x^{-2} is a solution of given differential equation.

c.7x^2y''-42y=0

y=x^3

y'=3x^2

y''=6x

Substitute the values in the differential equation

42x^3-42x^3=0

Hence, x^3 is a solution of given differential equation.

a-e^x,e^{-x}

b-x^{-2}

c-x^3

6 0
3 years ago
Read 2 more answers
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