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What will be the new position of the given point after rotating 180 about the origin

leva [86]

Answer: a) First quadrant

Step-by-step explanation:

From the given picture, the position of the given point is in third quadrant.

Every point in third quadrant are in the form of (-a,-b), where a and b are any positive numbers [both x and y axis are negative there]

Also after rotation of 180° the point (x,y) will map to (-x,-y)

therefore, after rotation of 180° the point (-a,-b) will map to

(-(-a),-(-b))=(a,b), where a and b are any positive numbers

Thus, the coordinate of image point =(a,b)

Since both x and y coordinate of the image are positive therefore it must lie in the first quadrant.

4 0

2 years ago

Read 2 more answers

05) A polynomial function f of degree(6) whose coefficients are real numbers has the zeros i, 4-i,2+i . Find the remaining zeros

arlik [135]

The degree of the polynomial function f is the number of zeros function f has.

The remaining zeros of the polynomial function are -i, 4 + i and 2 - i

<h3>How to determine the remaining zeros</h3>

The degrees of the polynomial is given as;

Degree = 6

The zeros are given as:

i, 4-i,2+i

The above numbers are complex numbers.

This means that, their conjugates are also zeros of the polynomial

Their conjugates are -i, 4 + i and 2 - i

Hence, the remaining zeros of the polynomial function are -i, 4 + i and 2 - i

Read more about polynomials at:

brainly.com/question/4142886

3 0

2 years ago

What is the probability of drawing the compliment of a king or a

inna [77]

Answer:

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

Step(i):-

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

$n( E_{1} ) = 4 _{C_{1} } = 4$

Let E₂ be the event of the card drawn being a queen

$n( E_{2} ) = 4 _{C_{1} } = 4$

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

step(ii):-

The probability of drawing of a king or a queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

$= \frac{4}{52} + \frac{4}{52}$

P( E₁ U E₂ ) = $\frac{8}{52}$

step(iii):-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards

$P(E_{1}UE_{2}) ^{-} = 1- P(E_{1} U E_{2} )$

$P(E_{1}UE_{2}) ^{-} = 1- \frac{8}{52}$

$P(E_{1}UE_{2}) ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846$

Conclusion:-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

5 0

2 years ago

Petra made the following observation:

AleksandrR [38]

Answer:A ratio compares two numbers or two quantities that are measured with the same unit. The ratio of a to b is written a to b,ab,ora:b. ... When a ratio is written in fraction form, the fraction should be simplified. If it is an improper fraction, we do not change it to a mixed number.

Step-by-step explanation:

A ratio compares two numbers or two quantities that are measured with the same unit. The ratio of a to b is written a to b,ab,ora:b. ... When a ratio is written in fraction form, the fraction should be simplified. If it is an improper fraction, we do not change it to a mixed number.

3 0

2 years ago

What is (x − 3)(x − 5) = 35

JulijaS [17]

Answer:

x=10 x=-2

Step-by-step explanation:

(x − 3)(x − 5) = 35

FOIL

x^2 -5x-3x+15 = 35

Combine like terms

x^2 -8x+15 = 35

Subtract 35 from each side

x^2 -8x+15-35 = 35-35

x^2 -8x-20 =0

Factor

What 2 numbers multiply to -20 and add to -8

-10*2 = -20

-10 +2 = -8

(x-10)(x+2) =0

Using the zero product property

x-10 =0 x+2 = 0

x=10 x=-2

6 0

2 years ago