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Anvisha [2.4K]
2 years ago
15

05) A polynomial function f of degree(6) whose coefficients are real numbers has the zeros i, 4-i,2+i . Find the remaining zeros

of (f) ​
Mathematics
1 answer:
arlik [135]2 years ago
3 0

The degree of the polynomial function f is the number of zeros function f has.

The remaining zeros of the polynomial function are -i, 4 + i and 2 - i

<h3>How to determine the remaining zeros</h3>

The degrees of the polynomial is given as;

Degree = 6

The zeros are given as:

i, 4-i,2+i

The above numbers are complex numbers.

This means that, their conjugates are also zeros of the polynomial

Their conjugates are -i, 4 + i and 2 - i

Hence, the remaining zeros of the polynomial function are -i, 4 + i and 2 - i

Read more about polynomials at:

brainly.com/question/4142886

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-7/3*5/9+13/3+4/9*-7/3=2
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The smallest composite number that can be written as a product of 4 different prime number are
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8 0
3 years ago
What is the slope of a line that is parallel to –x + 3y = 6 Responses 1/3 StartFragment, 1/3, -1 StartFragment, -1, 3 StartFragm
algol13

The slope of the line parallel to the line  –x + 3y = 6 is a 1/3 option (A) 1/3 is correct.

<h3>What is the slope?</h3>

The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).

\rm m =\dfrac{y_2-y_1}{x_2-x_1}

It is given that:

The equation of the line:

–x + 3y = 6

Write the equation in standard form:

y = x/3 + 6/3

y = x/3 + 2

m = 1/3

The slope of the line parallel to the line  –x + 3y = 6

M = 1/3

Thus, the slope of the line parallel to the line  –x + 3y = 6 is a 1/3 option (A) 1/3 is correct.

Learn more about the slope here:

brainly.com/question/3605446

#SPJ1

5 0
9 months ago
Tìm n: 133^5 + 110^5 + 84^5 + 27^5 = n^5
slavikrds [6]
Answer: n=144. . . . .
5 0
2 years ago
If log50=1.699 then what is the value of log(100)50?
JulijaS [17]

Answer:

   d.  0.849

Step-by-step explanation:

\log_{100}{(50)}=\dfrac{\log{50}}{\log{100}}=\dfrac{1.699}{2}=0.849

6 0
3 years ago
Read 2 more answers
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