Answer:
See below ~
Step-by-step explanation:
<u>Drawing the rectangle</u> (Refer attachment)
<u>Horizontal sides</u>
- There are two x-values present : 1 and 6
- Find the difference
- 6 - 1 = 5
- The horizontal sides of the rectangle are <u>5</u> units long
<u>Vertical sides</u>
- Two y-values are present : 4 and 5
- Find the difference
- 5 - 4 = 1
- The vertical sides of the rectangle are <u>1</u> unit long
<u>Perimeter</u>
- 2(Horizontal side + Vertical side)
- 2(5 + 1)
- 2(6)
- 12
- The perimeter of the rectangle is <u>12</u> units
Answer:
A) L = W + 6
B) L * W = 167 OR L = 167 / W
Substituting B) into A)
167 / W = W + 6
Multiplying both sides by "W" we get
167 = W^2 + 6W
W^2 + 6W -167
Solving by the quadratic formula
Width = 10.266
Length = 16.266
Step-by-step explanation:
One function you would be trying to minimize is
<span>f(x, y, z) = d² = (x - 4)² + y² + (z + 5)² </span>
<span>Your values for x, y, z, and λ would be correct, but </span>
<span>d² = (20/3 - 4)² + (8/3)² + (-7/3 + 5)² </span>
<span>d² = (8/3)² + (8/3)² + (8/3)² </span>
<span>d² = 64/3 </span>
<span>d = 8/sqrt(3) = 8sqrt(3)/3</span>
Answer:
Step-by-step explanation:
