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Verizon [17]
3 years ago
5

The area of the shaded region to the nearest tenth is __________.

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
4 0

Answer: 380 ft^2

Step-by-step explanation:

Length of sides of square=25

Diameter of semicircle=25

Radius=r=25/2=12.5

π=3.14

Area of square=length x length

Area of square=25 x 25=625

Area of semicircle=0.5 x π x r x r

Area of semicircle=0.5 x 3.14 x 12.5 x 12.5

Area of semicircle=245.3125

Area of shaded portion=area of square - area of semicircle

Area of shaded portion=625-245.3125

Area of shaded portion=379.6875

Area of shaded portion=380ft^2

approximately

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ivolga24 [154]

4.5 divided by 1.25 is 3.6

for peices in total it is 4.

for peices the right length it is 3

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Erica is buying a $205,000 home. She has decided to purchase 2 points in order to lower her interest rate. The appraisal fee is
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Which of the following results in the difference of two squares? (answer choices below)
Allushta [10]

Answer:

A

Step-by-step explanation:

Use signs inside the brackets as a guide

16×^2 - 25y^2

6 0
3 years ago
I need help asap pls and thank you ;)
olga55 [171]

Answer:

\text{Length of AB is }\frac{ah}{a+h}

Step-by-step explanation:

Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.

we have to find the length of AB.

Let the side of square i.e AB is x units.

As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°

⇒ CP||MP||AB

In ΔMNP and ΔCND

∠NCD=∠NMP     (∵ corresponding angles)

∠NDC=∠NPM     (∵ corresponding angles)

By AA similarity rule,  ΔMNP~ΔCND

Also, ΔKAP~ΔKPM by similarity rule as above.

Hence, corresponding sides are in proportion

\frac{ND}{NP}=\frac{CD}{MP} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{AB}{PM} \\\\\frac{ND}{NP}=\frac{x}{h} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{x}{h}\\\\\frac{NP}{ND}=\frac{h}{x} \thinspace\thinspace and\thinspace\thinspace \frac{KP}{KA}=\frac{h}{x}\\\\\frac{PD}{ND}=\frac{h}{x}-1 \thinspace\thinspace and\thinspace\thinspace \frac{AP}{KA}=\frac{h}{x}-1\\

KA(\frac{h}{x}-1)=AP

ND(\frac{h}{x}-1)=PD

Adding above two, we get

(KA+ND)(\frac{h}{x}-1)=(AP+PD)

⇒ (KN-AD)=\frac{x}{(\frac{h}{x}-1)}

⇒ a-x=\frac{x}{(\frac{h}{x}-1)}

⇒ a-x=\frac{x^2}{h-x}

⇒ x^2=ah-ax-xh+x^2

⇒ x(h+a)=ah

⇒ x=\frac{ah}{a+h}

3 0
3 years ago
A father is 32 years older than his son. In four years,
sergiy2304 [10]

Answer:

  • father: 36
  • son: 4

Step-by-step explanation:

Let s represent the son's age now. Then s+32 is the father's age. In 4 years, we have ...

  5(s+4) = (s+32)+4

  5s +20 = s +36 . . . . . eliminate parentheses

  4s = 16 . . . . . . . . . . . . subtract s+20

  s = 4

The son is now 4 years old; the father, 36.

_____

<em>Alternate solution</em>

In 4 years, the ratio of ages is ...

  father : son = 5 : 1

The difference of their ages at that time is 5-1 = 4 "ratio units". Since the difference in ages is 32 years, each ratio unit must stand for 32/4 = 8 years. That is, the future age ratio is ...

  father : son = 40 : 8

So, now (4 years earlier), the ages must be ...

  father: 36; son: 4.

5 0
3 years ago
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