Answer:

Explanation:
We are given the mass of two reactants, so this is a limiting reactant problem.
We know that we will need mases, moles, and molar masses, so, let's assemble all the data in one place, with molar masses above the formulas and masses below them.
M_r: 17.03 32.00 18.02
4NH₃ + 5O₂ ⟶ 4NO + 6H₂O
m/g: 70.1 70.1
Step 1. Calculate the moles of each reactant

Step 2. Identify the limiting reactant
Calculate the moles of H₂O we can obtain from each reactant.
From NH₃:
The molar ratio of H₂O:NH₃ is 6:4.

From O₂:
The molar ratio of H₂O:O₂ is 6:5.

O₂ is the limiting reactant because it gives the smaller amount of H₂O.
Step 3. Calculate the theoretical yield.

Answer:
the stoichiometric coefficient for cobalt is 3
Explanation:
the unbalanced reaction would be
Co(NO₃)₂+ Al → Al(NO₃)₃ + Co
One way to solve is to build a system of linear equations for each element (or group as NO₃) , knowing that the number of atoms of each element is conserved.
For smaller reactions a quick way to solve it can be:
- First the Co as product and as reactant needs to have the same stoichiometric coefficient
- Then the Al as product and as reactant needs to have the same stoichiometric coefficient
- After that we look at the nitrates . There are 2 as reactants and 3 as products . Since the common multiple is 6 then multiply the reactant by 3 and the product by 2.
Finally the balanced equation will be
3 Co(NO₃)₂+ 2 Al → 2 Al(NO₃)₃ + 3 Co
then the stoichiometric coefficient for cobalt is 3
Answer:The change in concentration of a reactant or product per unit time
Explanation:
Answer: divide by 946.353
= 1.58 x 10^-4 or 0.000159
Explanation: