Calculate the number of grams contained in each of the following number of moles. Report your answer with the appropriate number
a. 0.410 mol of NaCl (sodium chloride)
b. 4.80 mol of C2H4 (ethylene)
Mass in gram of NaCl = 23.96 g
Mass in gram of C2H4 = 134.64 g
<h3>Part 1.</h3>Given data:
Moles of NaCl =0.42 mol
Molecular mass of NaCl = 58.44 g/mol
Mass in grams of NaCl = ?
Solution:
The formula of number of moles = Mass in grams / Molecular mass
For the mass in grams = Molecular mass × Number of moles
By putting the given values in second formula:
Mass in grams of NaCl = 58.44 × 0.41
= 23.96 g
<u>So the sodium chloride is 0.42 molar it means its mass in gram is 23.96.</u>
<h3>Part 2.</h3>Given data:
Moles of C2H4 = 4.80 mol
Molecular mass of C2H4 = 28.05 g/mol
Mass in grams of C2H4 = ?
Solution:
The formula of number of moles = Mass in grams / Molecular mass
For the mass in grams = Molecular mass × Number of moles
By putting the given values in second formula:
Mass in grams of C2H4 = 28.05 × 4.8
= 134.64 g
<u>So 134.64 grams of ethylene contains 4.8 mol of ethylene.</u>
<h2 />
<u>Answers:</u>
a. 131.85 grams
b. 134.69 grams
To calculate the number of grams in the number of moles given for each compound, consider the formula:
<em>Moles = No. of grams / molar mass</em>
Therefore, to find the gram it will become:
<em>No. of grams = moles x molar mass</em>
a. 0.410 mol of NaCl (sodium chloride)
Molar mass of NaCl = (286.14 + 35.45) = 321.59
No. of grams = moles x molar mass
No. of grams = 0.410 x 321.59 = 131.85 grams
b. 4.80 mol of C2H4 (ethylene)
Molar mass of C2H4 = (12.01 x 2) + (1.01 x 4) = 28.06
No. of grams = moles x molar mass
No. of grams = 4.80 x 28.06 = 134.69 grams
1) To find the change in enthalpy, determine the difference between the potential energy of the products and the potential energy of the reactants. (on this diagram, C-A) To find the activation energy, find the difference between the potential energy of the reactants and the "peak" of the curve (on this diagram, B-A). For this diagram, both the enthalpy and activation energy are positive.
2) If the reaction was exothermic, enthalpy would be negative, and the potential energy of the reactants would be greater than the potential energy of the products.
Answer:
Mg(OH)2 + 2HCI ⇒ MgCI2 + 2H2O
Explanation:
In order to balance a chemical equation you need to make sure both sides of the equations are equal.
Mg(OH)2 + 2HCI = MgCI2 + H2O
Mg = 1
Oh = 2
HCI = 2
Products:
Mg = 1
CI = 2
H = 2
O = 1
2H20 = 1 × 2 = 2
2 × 2 = 4
2HCI
1 × 2 = 2
Mg(OH)2 + 2HCI ⇒ MgCI2 + 2H2O
Hope this helps.

Explanation:
Mass = volume × density
Mass = 652 cm³ × 21.45 g/cm³
= 13985.4 g
Explanation:
so you Neva add or change a subscript