the derivative of ln(lnx^3) is
.
<u>Step-by-step explanation:</u>
Here we have to find the derivative of ln(lnx^3) , Let's find out:
We have ,
, Let's differentiate it w.r.t x :
⇒ 
Let 
⇒ 
⇒ 
⇒ 
Let 
⇒ 
⇒ 
⇒
⇒ 
Putting value of u & v we get:
⇒ 
⇒
{
}
⇒ 
⇒ 
Therefore , the derivative of ln(lnx^3) is
.
Answer:
56+56=112 16kg
112+42=154 42 = 6kg
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
given the endpoints of a line segment
(x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
[
(x₁ + x₂),
(y₁ + y₂) ]
For example
consider the endpoints (4, 2) and (6, - 4)
midpoint = [
(4 + 6),
(2 - 4)] = (5, - 1)
Step 1
Given; The table below
Required;
Step 2
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
If the graph has a negative value for a then it will look like that seen below;
This graph is from the table
The answer thus will be;
Given:
are in geometric sequences.
To find:
The value of x.
Solution:
If a, b, c are in geometric sequences, then

...(i)
It is given that
are in geometric sequences. By using (i), we get




On further simplification, we get



Therefore, the value of x is 0.