Question

Polynomials perimeter and area photo above

Answer 1

Answer: Perimeter $4x^{2} -6$  or  $2(2x^{2} -3)$ units

Area $-12x^{3} - 5x^{2} + 42x -20$  or $2(-6x^{3} -5x^{2} + 21x -20)$ square units

Step-by-step explanation:

A. Perimeter is Twice the length plus twice the length. P =2(l + w)

or P = 2L + 2W . Substitute the values given into the formula and Calculate.

P = 2[(2x + 5)(x-1) + 2(2-3x)] . becomes $2(2x^{2} +3x -5) + 2(2-3x)$,

then $4x^{2} + 6x - 10 - 6x +4$   add like terms and simplify $4x^{2} -6$

B. Area is Length times Width. Substitute the given values and calculate.

(2x + 5)(x-1)×(2-3x)  (2x + 5)(x-1)(-3x+2)

$-12x^{3} - 5x^{2} + 42x -20$

It is difficult to imagine an actual rectangle with such dimensions. It's math theory.