Okay...so since 90 degrees out of 360 is taken out that means that the hemisphere is only 250 degrees. That's only 3/4 of a hemisphere. So, you need to find the volume of the hemisphere as if it were a sphere. Then, you divide that by 2 to get the volume of the hemisphere. Then, you multiply it by 3/4 to get the volume of your sliced hemisphere.

3 0

3 years ago

Given the circle with the equation (x - 3)2 + y2 = 49, determine the location of each point with respect to the graph of the cir

Bas_tet [7]

To find out if a point is inside, on, or outside a circle, we need to substitute the ordered pair into the equation of the circle:
(x-xc)^2+(y-yc)^2=r^2
where (xc,yc) is the centre of the circle, and r=radius of the circle.

If the left-hand side [(x-xc)^2+(y-yc)^2] is less than r^2, then point (x,y) is INSIDE the circle. If the left-hand side is equal to r^2, the point is ON the circle.
Finally, if the left-hand side is greater than r^2, the point is OUTSIDE the circle.

For the given problem, we have xc=3, yc=0, or centre at (3,0), r=sqrt(49)=7
(x-xc)^2+(y-yc)^2=r^2 => (x-3)^2+y^2=7^2

A. (-1,1),
(x-3)^2+y^2=7^2 => (-1-3)^2+1^2=16+1=17 <49 [inside circle]

B. (10,0)
(x-3)^2+y^2=7^2 => (10-3)^2+0^2=49+0=49 [on circle]

C. (4,-8)
(x-3)^2+y^2=7^2 => (4-3)^2+(-8)^2=1+64=65 > 49 [outside circle]

5 0

3 years ago

-3(x+0.6)=6(x+2.4)<br> Could you possibly show the work also?

kap26 [50]

Multiple-3(x+0.6) and 6(x+2.4) you will get -3x-1.8=6x+14.4 then you add -3x + 6x you will get -9x=14.4+1.8 you add 14.4+1.8 that will give you 16.2 then divide that by -9

3 0

3 years ago