Answer:
Explanation:
<u>1) Data:</u>
a) n = ?
b) V = 50.0 dm³ = 50.0 liter
c) p = 100.0 kPa
d) T = 50 °C
<u>2) Physical law:</u>
<u>3) Constants:</u>
- R = 0.08206 atm-liter / K-mol
<u>4) Unit conversions:</u>
- T = 50 + 273.15 K = 323.15 K
- P = 100.0 kPa × (1 amt /101,325 kPa) = 0.9869 atm
<u>5) Solution:</u>
- n = 0.9869 atm × 50.0 liter / (0.08206 atm-liter /K-mol × 323.15 K)
The common ion effect is the decreased solubility of the ionic precipitate in the solution. To promote the precipitation of the calcium sulfate, magnesium sulfate must be added.
<h3>What is the common ion effect?</h3>
It is a phenomenon that is due to the addition of the common ion already present in the solution that affects the equilibrium and is used to decrease the solubility of the solute present in the solution to increase the precipitation rate.
Magnesium sulfate will be added to the solution as it already contains the sulfate ion in the form of calcium sulfate. This will increase the precipitation of the compound as the common ion added will decrease the solubility.
Therefore, magnesium sulfate will be added to promote precipitation.
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Answer:
b)
Explanation:
the data for the average height of the plants in all three trails contains error
Answer:
B.
Explanation:
I believe it is B, it could be C too.
To answer this item, we assume that oxygen behaves ideally such that it is able to fulfill the following equation,
PV = nRT
If we are to retain constant the variable n and V.
The percent yield can therefore be solved through the following calculation,
n = (10.5 L)/(22.4 L) x 100%
Simplifying,
n = 46.875%
Answer: 48.87%