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3 years ago

Why is BrCl5 nonpolar when it's Asymmetrical? Aren't symmetrical molecules suppposed to be polar?

2 answers:

8 0

Although there exists a dipole moment in the molecule, I guess its nonpolar because the dipole is very small as the electronegativity difference between the Br and Cl is very low and so it can be neglected.

Mars2501 [29]3 years ago

4 0

Answer:

BrCl₅ is an asymmetrical molecule because it has one lone pair and five atoms bonded to the central atom. Due to low difference of electronegativities, BrCl₅ is a nonpolar molecule.

Explanation:

According to the Linus Pauling scale, the difference between their electronegativities Δx can be determined if the link will be:

polar: 0 ≤ Δx ≤ 0.4

nonpolar: 0.5 ≤ Δx ≤ 1.6

ionic: 1.7 ≤ Δx ≤ 2.0

Br-Cl bonds are nonpolar because the difference between their electronegativities is:

Br: 2.96

Cl: 3.16

Δx= 3.16 - 2.96 = 0.2

BrCl₅ has nonpolar bonds.

You might be interested in

1. What is the best means to separate ammonium chloride, sand, and zinc chloride? And a

ozzi

1. A mixture of ammonium chloride, sand, and zinc chloride should be separated by sublimation.

2. A mixture of zinc chloride and silver chloride should be separated through crystallization.

<h3>What is a separation technique?</h3>

A separation technique can be defined as a technique that is typically used to separate or convert two (2) or more mixture and solution of chemical substances into distinct product such as chemical compounds or elements.

<h3>The types of separation technique.</h3>

In Chemistry, there are various types of separation technique used for the separation of mixtures or solutions and these include:

Crystallization

Fractional distillation

Filtration

Evaporation

Sublimation

Decantation

Simple distillation

Chromatography

In this scenario, the most effective and efficient means to separate a mixture of ammonium chloride, sand, and zinc chloride is by sublimation from solid to gas state.

On the other hand, the best means to separate a mixture of zinc chloride and silver chloride is through crystallization.

Read more on crystallization here: brainly.com/question/4980962

7 0

2 years ago

Which component of solution is dissolving medium? a.solute b.solvent

liubo4ka [24]

Answer:

Solvent

Explanation:

7 0

3 years ago

Express the concentration of a 0.0390 M aqueous solution of fluoride, F − , in mass percentage and in parts per million (ppm). A

Vadim26 [7]

Answer:

Mass percentage → 0.074 %

[F⁻] = 741 ppm

Explanation:

Aqueous solution of flouride → [F⁻] = 0.0390 M

It means that in 1L of solution, we have 0.0390 moles of F⁻

We need the mass of solution and the mass of 0.0390 moles of F⁻

Mass of solution can be determined by density:

1g/mL = Mass of solution / 1000 mL

Note: 1L = 1000mL

Mass of solution: 1000 g

Moles of F⁻ → 0.0390 moles . 19g /1 mol = 0.741 g

Mass percentage → (Mass of solute / Mass of solution) . 100

(0.741 g / 1000 g) . 100 = 0.074 %

Ppm = mass of solute . 10⁶ / mass of solution (mg/kg)

0.741 g . 1000 mg/1g = 741 mg

1000 g . 1 kg/1000 g = 1kg

741 mg/1kg = 741 ppm

5 0

3 years ago

Balance each of the following redox reactions occurring in acidic aqueous solution.

dmitriy555 [2]

Answer:

Part A : Zn(s) + Sn²⁺(aq) → Zn²⁺(aq) + Sn(s).

Part B : 3Mg(s) + 2Cr³⁺(aq) → 3Mg²⁺(aq) + 2Cr(s).

Part C: 3MnO₄⁻ + 24H⁺ + 5Al → 5Al³⁺ + 3Mn²⁺ + 12H₂O.

Explanation:

<em>Part A : Zn(s) + Sn²⁺(aq) → Zn²⁺(aq) + Sn(s), Express your answer as a chemical equation. Identify all of the phases in your answer. </em>

It is balanced as written: Zn(s) + Sn²⁺(aq) → Zn²⁺(aq) + Sn(s).

The two half reactions are:

The oxidation reaction: Zn(s) → Zn²⁺(aq) + 2e.

The reduction reaction: Sn²⁺(aq) + 2e → Sn(s).

To obtain the net redox reaction, we add the two-half reactions as the no. of electrons in the two-half reactions is equal.

So, the net chemical equation is:

<em>Part B: Mg(s) + Cr³⁺(aq) → Mg²⁺(aq) + Cr(s), Express your answer as a chemical equation. Identify all of the phases in your answer. </em>

To balance and write the net chemical equation, we should write the two-half reactions:

The two half reactions are:

The oxidation reaction: Mg(s) → Mg²⁺(aq) + 2e.

The reduction reaction: Cr³⁺(aq) + 3e → Cr(s).

To obtain the net redox reaction, we multiply the oxidation reaction by 3 (3Mg(s) → 3Mg²⁺(aq) + 6e) and the reduction reaction by 2 (2Cr³⁺(aq) + 6e → 2Cr(s)) to equalize the no. of electrons in the two-half reactions.

So, the net redox reaction will be:

<em>Part C : MnO⁴⁻(aq) + Al(s) → Mn²⁺(aq) + Al³⁺(aq), Express your answer as a chemical equation. Identify all of the phases in your answer.</em>

To balance and write the net chemical equation, we should write the two-half reactions:

The two half reactions are:

The oxidation reaction: Al → Al³⁺ + 3e.

The reduction reaction: MnO₄⁻ + 8H⁺ + 5e → Mn²⁺ + 4H₂O.

To obtain the net redox reaction, we multiply the oxidation reaction by 5 (5Al → 5Al³⁺ + 15e) and the reduction reaction by 3 (3MnO₄⁻ + 24H⁺ + 15e → 3Mn²⁺ + 12H₂O) to equalize the no. of electrons in the two-half reactions.

So, the net redox reaction will be:

4 0

3 years ago

Normal melting point: 658 C Normal boiling point: 2467 C

taurus [48]

{ 12 mol * 27 g / mol * 0.902 j/gdeg C* ( 658 -72 ) deg C + 12 * 27 * 3.95 }
quantity of energy required to heat 12 mol of aluminium for 72 deg C to its melting point 658 C

so energy applied is 1451 057 . 33 J

5 0

3 years ago

Read 2 more answers