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viktelen [127]
4 years ago
12

Why is BrCl5 nonpolar when it's Asymmetrical? Aren't symmetrical molecules suppposed to be polar?

Chemistry
2 answers:
Svet_ta [14]4 years ago
8 0
Although there exists a dipole moment in the molecule, I guess its nonpolar because the dipole is very small as the electronegativity difference between the Br and Cl is very low and so it can be neglected.
Mars2501 [29]4 years ago
4 0

Answer:

BrCl₅ is an asymmetrical molecule because it has one lone pair and five atoms bonded to the central atom. Due to low difference of electronegativities, BrCl₅ is a nonpolar molecule.

Explanation:

According to the Linus Pauling scale, the difference between their electronegativities Δx can be determined if the link will be:

  • polar: 0 ≤ Δx ≤ 0.4
  • nonpolar: 0.5 ≤ Δx ≤ 1.6
  • ionic: 1.7 ≤ Δx ≤ 2.0

Br-Cl bonds are nonpolar because the difference between their electronegativities is:

Br: 2.96

Cl: 3.16

Δx= 3.16 - 2.96 = 0.2

BrCl₅ has nonpolar bonds.

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marshall27 [118]
C is the correct answer
7 0
2 years ago
How many grams of water are produced from 100 grams of oxygen?
Allisa [31]

Answer:

28,125 g

Explanation:

m(O₂) = 100 g

n(O₂) =M(O₂)/m(O₂)=32 gram per mole / 100 g = 0,32 mole

O₂ + 2H₂ ⇒ 2H₂O  ,  n(H₂O) = 2 × n(O₂)

m(H₂O) = M(H₂O)/2 × n(O₂) = 18 grams per mole / 2 × 0,32 mole = 28,125 g

6 0
3 years ago
Show the curved-arrow mechanism for the Claisen condensation of ethyl ethanoate treated with ethoxide ion. Include all formal ch
Anna [14]

Answer:

See explaination

Explanation:

Please kindly check out the attached files for the curved-arrow mechanism for the Claisen condensation of ethyl ethanoate treated with ethoxide ion.

4 0
3 years ago
How do the Carnivorous plants survive without soil?
Mkey [24]
Answer:

Carnivorous plants are easy to grow, if you follow a few, simple rules.

Wet all of the time.
Mineral-free water.
Mineral-free soil.
Lots of light.


Wet all of the time.
Carnivorous plants are native to bogs and similar nutrient-poor habitats. As a consequence, the plants live in conditions that are constantly damp. To grow healthy carnivorous plants, it is important to duplicate their habitat as closely as possible. Keep the soil wet or at least damp all of the time. The easiest way to do this is use the tray method. Set the pots in a tray or saucer, and keep water in it at all times. Pitcher plants can grow in soggy soil with the water level in the saucer as deep as 1/2 the pot, but most carnivorous plants prefer damp to wet soil, so keep the water at about 1/4 inch and refill as soon as it is nearly gone. Water from below, by adding water to the tray, rather than watering the plant. This will avoid washing away the sticky muscilage of the sundews and butterworts and keep from closing the flytraps with a false alarm.


Mineral-free water.
Always use mineral-free water with your carnivorous plants, such as rainwater or distilled water. Try keeping a bucket near the downspout to collect rainwater. Distilled water can be purchased at the grocery store, but avoid bottled drinking water. There are simply too many minerals in it. The condensation line from an air conditioner or heat pump is another source of mineral-free water. Reverse-osmosis water is fine to use. Carnivorous plants grow in nutrient poor soils. The minerals from tap water can “over-fertilize” and “burn out” the plants. In a pinch, tap water will work for a short while, but flush out the minerals with generous portions of rainwater, when it is available.


Mineral-free soil.
The nutrient poor soils to which the carnivorous plants have adapted are often rich in peat and sand. This can be duplicated with a soil mixture of sphagnum peat moss and horticultural sand. Be sure to check the peat label for sphagnum moss. Other types will not work well. The sand should be clean and washed. Play box sand is great, and so is horticultural sand. Avoid “contractor’s sand” which will contain fine dust, silt, clay and other minerals. Never use beach sand or limestone based sand. The salt content will harm the plants. The ratio of the mix is not critical, 1 part peat with 1 part sand works well for most carnivorous plants. Flytraps prefer a bit more sand, and nepenthes prefer much more peat. Use plastic pots, as terra cotta pots will leach out minerals over time and stress your plants.

Explanation:


Kayo na Po bahala magpaigsi
5 0
3 years ago
What is the ph (to nearest 0.01 ph unit) of a solution prepared by mixing 58.0 ml of 0.0179 m naoh and 60.0 ml of 0.0294 m ba(oh
Nina [5.8K]

Answer: -

12.59

Explanation: -

Strength of NaOH = 0.0179 M

Volume of NaOH = 58.0 mL = 58.0/1000 = 0.058 L

Number of moles = 0.0179 M x 0.058 L

= 1.04 x 10⁻³ mol

Mol of [OH⁻] given by NaOH = 1.04 x 10⁻³ mol

Strength of Ba(OH)₂ = 0.0294 M

Volume of Ba(OH)₂ = 60.0 mL = 60.0/1000 = 0.060 L

Number of moles = 0.0294 M x 0.060 L

= 1.76 x 10⁻³ mol

Mol of [OH⁻] given by Ba(OH)₂ =2 x 1.76 x 10⁻³ mol

Total [OH⁻] = 1.04 x 10⁻³ mol + 2 x 1.76 x 10⁻³ mol

= 4.56 x 10⁻³ mol

Total volume of the mixture = 58.0 + 60.0

= 118.0 mL

118.0 mL of the solution has 4.56 x 10⁻³ mol [OH⁻]

1000 mL of the solution has \frac{4.56 x 10-3 mol x 1000mL }{118 mL}

= 0.0386 mol

Using the relation

pOH = - log [OH-]

= - log 0.0386

= 1.41

Using the relation

pH + pOH = 14

pH = 14 - 1.41

= 12.59

5 0
3 years ago
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