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3 years ago

11

Find the equation of the linear function represented by the table below in slope intercept form.

1 answer:

grigory [225]3 years ago

5 0

Answer:

y = -3x - 2

Step-by-step explanation:

slope (m) = (-8 - -5) / (2 - 1) ... difference of y/difference of x

m = -3

y = mx + b

y = -3x + b

for (3,-11) b = y + 3x = -11 + 3x3 = -2

equation: y = -3x - 2

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I need help this is due tonight

leva [86]

Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

First, let's establish that, they are co-interior angles on parallel lines. We can identify this as they form a 'C' shape on parallel lines.

Co-interior angles add up to 180°.

Therefore:

( x + 27 )° + ( 3x - 25 )° = 180°

x + 3x = 180 - 27 + 25

4x = 178

x = 178 / 4

x = 89 / 2

x = 44.5°

Hope this helps! <3

4 0

3 years ago

) If the gradient of ff is ∇f=xi⃗ +yj⃗ +3zyk⃗ ∇f=xi→+yj→+3zyk→ and the point P=(−6,−6,−2)P=(−6,−6,−2) lies on the level surface

Paha777 [63]

Answer:

-3x-3y-z=38

Step-by-step explanation:

To find the equation of the tangent plane you can use

$\bigtriangledown f_x(x_0,y_0,z_0)(x-x_0)+\bigtriangledown f_y(x_0,y_0,z_0)(y-y_0)+\bigtriangledown f_z(x_0,y_0,z_0)(z-z_0)=0$

the point P is (-6,-6,-2). Hence you have

$(-6)(x-(-6))+(-6)(y-(-6))+(-2)(z-(-2))=0\\-6x-36-6y-36-2z-4=0\\-6x-6y-2z=76\\-3x-3y-z=38$

hope this helps!!

5 0

3 years ago

Can someone please help me with this:)

madam [21]

Answer: c

Step-by-step explanation:

3 0

3 years ago

the quadratic of a certain quadratic function has no x-interecepts which of the following are possible values for discriminants

Snowcat [4.5K]

Answer:

Some possible values are -5, -3, -2.

Step-by-step explanation:

Basically if d(discriminant)

d > 0 = 2 x intercepts,

d = 0 means one x intercept

d < 0 = 0 x intercepts

:) Hoped this helped :)

4 0

3 years ago

Find the transition matrix from B to B'. B = {(-1,2), (3, 4)), B' = {(1, 0), (0, 1)} STEP 1: Begin by forming the following matr

8_murik_8 [283]

Answer: The required matrix is

$T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .$

Step-by-step explanation: We are given to find the transition matrix from the bases B to B' as given below :

B = {(-1,2), (3, 4)) and B' = {(1, 0), (0, 1)}.

Let us consider two real numbers a, b such that

$(-1,2)=a(1,0)+b(0,1)\\\\\Rightarrow (-1,2)=(a,b)\\\\\Rightarrow a=-1,b=2.$

Again, let us consider reals c and d such that

$(3,4)=c(1,0)+d(0,1)\\\\\Rightarrow (3,4)=(c,d)\\\\\Rightarrow c=3,d=4.$

Therefore, the transition matrix is given by

$T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .$

Thus, the required matrix is

$T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .$

7 0

3 years ago