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Ket [755]
3 years ago
11

What is the solution to the linear equation 4b + 6 = 2 - b+ 4

Mathematics
1 answer:
inessss [21]3 years ago
5 0

Final Answer: b = 0

Steps/Reasons/Explanation:

Question: What is the solution to the linear equation 4b + 6 = 2 - b + 4?

<u>Step 1</u>: Simplify 2 - b + 4 to 6 - b.

4b + 6 = 6 - b

<u>Step 2</u>: Cancel 6 on both sides.

4b = -b

<u>Step 3</u>: Subtract -b from both sides.

4b + b = 0

<u>Step 4</u>: Simplify 4b + b to 5b.

5b = 0

<u>Step 5</u>: Divide both sides by 5.

b = 0

~I hope I helped you :)~

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Step-by-step explanation:

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2 years ago
Probability. A professor rides his bike to work some days and drives his car on the other days. On any day there is an 80% chanc
Artyom0805 [142]

Answer:

0.09

Step-by-step explanation:

Given :

P(bike) = 0.8

P(car) = 0.2

P(Late given car) = P(Late | car) = 0.05

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Probability that professor is late :

P(late) = [P(Late | car) * p(car)] + [p(Late | bike) * p(bike)]

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3 years ago
Write the following equation in slope-intercept form.<br> 1/3 - y+6=0
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Step-by-step explanation:

4 0
3 years ago
What is the greatest common factor of 15x^3y^2 and 20x^4y^4?
Vanyuwa [196]
<h3>What is the greatest common factor of 15x³y² and 20x⁴y⁴? ​</h3>

​<em>First we have to find the factors of 15x³y²</em>

<em>15x³y² = 3 * 5x³y² ​</em>

<em>​Then we have to find the factors of 20x⁴y⁴</em>

<em>​20x⁴y⁴ = 2²x¹y² * 5x³y²</em>

<em>Now we have to find the common factors to both numbers.​</em>

<em>The common factors are </em><em>5x³y²</em>

Answer : GCF = (15x³y²,20x⁴y⁴) = 5x³y²​

​Hope this helps!​​​​

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6 0
3 years ago
A train leaves San Diego at 1:00 pm. A second train leaves the same city in the same direction at 3:00 pm. The second train trav
Soloha48 [4]

Answer:

The speed of the first train is 45 mph and the speed of the second train is 75 mph

Step-by-step explanation:

Let x represent the speed of the first train in mph. Since the second train, is 30 mph faster then the first, therefore the speed of the second train is (x + 30).

The first train leaves at 1:00 pm, therefore at 6:00 pm, the time taken is 5 hours. Therefore the distance covered by the first train at 6:00 pm = x mph * 5 hours = 5x miles

The second train leaves at 3:00 pm, therefore at 6:00 pm, the time taken is 3 hours. Therefore the distance covered by the second train at 6:00 pm = (x + 30) mph * 3 hours = (3x + 90) miles

Since the second train overtakes the first at 6:00 pm, hence:

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x = 45

Therefore the speed of the first train is 45 mph and the speed of the second train is 75 mph (45 mph + 30 mph).

7 0
3 years ago
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