(701+y)/(3+1)<200
(701+y)/4<200
701+y<800
y<99
So the most yards they can allow in the next game is 98 yards
The answer to your question is b
Answer:
They will have 24 babies in one year
Step-by-step explanation:
All you need to do is add 6 babies every two months starting in January. Include January as the gerbils having their first 6 babies. Every 2 months includes 4 months out of the year. 6*4 = 24 babies.
The answer is that she would have been up to bat 19 times
Answer:
C.I. = (2.297, 11.703)
Step-by-step explanation:
The t-statistic for difference of mean is given by,
Here, = 84
= 7
s₁ = 4
n₁ = 12
s₂ = 6
n₂ = 18
Substituting all value in formula,
We get, t = -3.541 at 28 degree of freedom.
Using this formula, we get, t = 1.5342
Therefore, based on the data provided, the 99% confidence interval for the difference between the population means is: 2.297 < < 11.703
which indicates that we are 99% confident that the true difference between population means is contained by the interval (2.297, 11.703)