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mixas84 [53]
3 years ago
8

What is the slope of a line that is perpendicular to the

Mathematics
1 answer:
alexgriva [62]3 years ago
5 0

Answer:

The slope of a line that is perpendicular to the line

shown in the graph is = 4

Hence, option 'd' is true.

Step-by-step explanation:

From the line equation, let us take two points

  • (0, 2)
  • (4, 1)

Finding the slope between two points

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(0,\:2\right),\:\left(x_2,\:y_2\right)=\left(4,\:1\right)

m=\frac{1-2}{4-0}

m=-\frac{1}{4}

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

The slope of the perpendicular line will be:

-\frac{1}{-\frac{1}{4}}=4

Thus, the slope of a line that is perpendicular to the line

shown in the graph is = 4

Hence, option 'd' is true.

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Answer:

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2 years ago
Factor the quadratic equation below to reveal the solutions. X^2+4x-21=-9
a_sh-v [17]

Answer:

x = 3 and x = -7

Step-by-step explanation:

The given quadratic equation is x^2+4x-21=0. We need to find the solution of this equation.

If the equation is in the form of ax^2+bx+c=0, then its solutions are given by :

x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

Here, a = 1, b = 4 and c = -21

Plugging all the values in the value of x, such that :

x=\dfrac{-b+ \sqrt{b^2-4ac} }{2a},\dfrac{-b- \sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-4+ \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)},\dfrac{-4- \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)}\\\\x=3, -7

So, the solutions of the quadratic equation are 3 and -7.      

6 0
3 years ago
How do u factor..<br>x^2 + 10× - 2400 = 0 ​
Lunna [17]

Answer:

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3 0
3 years ago
Read 2 more answers
-0.2 + 7/10 plz help I’m stuck
Lelechka [254]

(-0.2) + (7÷10) =

(-0.2) + 0.70 =

0.5

Hope that helps!


6 0
3 years ago
Triangle s=71.5 R=71.5. What is the measure of T?
Dovator [93]
T is 37

37+71.5+71.5=180
6 0
3 years ago
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