The rule of exponential multiplication is (a^x)*(a^y)=a^(x+y)
using this with your expression, we can do
(10^1)*(10^3)*(10^2)=10^(1+3+2)=10^6
Final answer:
10^6 or 1 million
Hope I helped :)
Answer:
(5/2 , 1)
Step-by-step explanation:
4X – 3y = 7
4x + y = 11
———————
Multiply a -1 to the bottom equation to get the 4x as a negative so it cancels out.
4x - 3y = 7
-4x - y = -11
——————
-4y = -4
Divide by -4
y = 1
Substitute the value of y into one of the equations and solve
4x - 3(1) = 7
4x -3 = 7
4x = 10
Divide by 4
X = 10/4
Simplify by dividing by 2
x = 5/2
Therefore the answer is (5/2, 1 )
<u>answer (in words)</u>
FALSE. the coordinate pair (5, 2) is not a solution to the equation
. in order to figure out whether or not the statement is true or false, plug the
and
values from the coordinate pair (5, 2) into the given equation,
. if both sides of the equation end up equal, the coordinate pair is a solution to the equation. if not, the coordinate pair is not a solution to that equation.
<em>(i hope i explained that well enough, i'm better at explaining it algebraically as opposed to putting it into words lol)</em>
<u>answer (algebraic/steps for solving)</u>
first, plug in 5 for
in the equation
.
⇒ 
then plug in 2 for
.
⇒ 
now your equation is
. all that's left to do is to simplify. you can do this in whatever order you'd like, but i'll start with multiplying 2 · 5.
⇒ 
multiply 3 · 2.
⇒ 
add 10 + 6.
⇒ 
16 and 10 are <em>not</em> equal, therefore (5, 2) is not a solution to the equation
. in order for a coordinate pair to be the solution to an equation, both sides of the equation need to end up equal after solving and simplifying.
i hope this helps! have a great rest of your day <3
X + y = 24....multiply by -3
3x + 5y = 100
---------------
-3x - 3y = - 72 (result of multiplying by -3)
3x + 5y = 100
--------------add
2y = 28
y = 28/2
y = 14
x + y = 24
x + 14 = 24
x = 24 - 14
x = 10
solution is (10,14)...and x represents 3 point q's and y represents 5 point q's......so this tells me there are 10 three point q's and 14 five point q's.