3 years ago

Please help me with me math study guide.

Mathematics

1 answer:

julsineya [31]3 years ago

7 0

What grade level is this???????????

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Use the equation v=10/p to determine the pressure when the volume is 12 liters

Alex777 [14]

V = 10/p
12 = 10/p
10/12 = 5/6 or 0.83 (3 repeating)
so p = 5/6 or 0.83 (3 repeating)

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3 years ago

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Sonji has $5.25 in nickels and dimes . The coin value can modeled by the equation 0.10+0.05n=5.25, where d represents the number

Lyrx [107]

63

.10d + .05n = 5.25

.10(21) + .05n = 5.25

2.1 + .05n = 5.25

.05n = 3.15

n = 3.15/.05

n = 63

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3 years ago

What is the value of -17 - (-1)?

AlladinOne [14]

Answer: -16

Explanation: Since you are subtracting a negative number from -17, you are actually just adding that number to it, and -17 + 1 is -16

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2 years ago

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Multiply. 3 1/2 ⋅ 2 2/3 ( A. 9 1/6 B. 21 1/16 C. 9/13 D. 9 2/3 )

Vesna [10]

I think that can be D

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2 years ago

Show that √(1-cos A/1+cos A) =cosec A - cot A

Gennadij [26K]

Hi there!

$\sqrt{\frac{1-cosA}{1+cosA}} =$

We can begin by multiplying by its conjugate:

$\sqrt{\frac{1-cosA}{1+cosA}} * \sqrt{\frac{1+cosA}{1+cosA}} = \\\\\sqrt{\frac{(1-cosA)(1 + cosA)}{(1+cosA)(1 + cosA)}} =$

Simplify using the identity:

$1 - cos^2A = sin^2A$

$\sqrt{\frac{(1-cos^2A)}{(1+cosA)^2}} =\\\\\sqrt{\frac{(sin^2A)}{(1+cosA)^2}} =$

Take the square root of the expression:

${\frac{sinA}{1+cosA} =$

Multiply again by the conjugate to get a SINGLE term in the denominator:

${\frac{sinA}{1+cosA} * {\frac{1-cosA}{1-cosA} =\\$

Simplify:

${\frac{sinA(1-cosA)}{1-cos^2A} =$

Use the above trig identity one more:

${\frac{sinA(1-cosA)}{sin^2A} =$

Cancel out sinA:

${\frac{(1-cosA)}{sinA} =$

Split the fraction into two:

${\frac{1}{sinA} - \frac{cosA}{sinA} =$

Recall:

$1/sinA = cscA\\\\cosA/sinA = cotA$

Simplify:

$\frac{1}{sinA} + \frac{cosA}{sinA} = \boxed{cscA - cotA}$

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2 years ago