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zimovet [89]
3 years ago
10

Plss help. i’m not sure how to do this so please help. i’d appreciate it

Mathematics
1 answer:
vazorg [7]3 years ago
5 0

Answer:

its a file to powerpoint hope thats ok

Step-by-step explanation:

Download pptx
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Find all derivatives of y^n of the function y=√x+5
quester [9]

Hello,

As somebody has distroyed my question, (may be he have not understood ?)

i will reply to y=(√x)+5

\displaystyle \boxed{\dfrac{d^n y}{dx^n} =(-1)^n*n!! *\dfrac{1}{2^n} *x^{-\frac{2n+1}{2} }\\}\\y'=\dfrac{1}{2} *x^{-\frac{1}{2}} \\\\y''=-\dfrac{1}{4} *x^{-\frac{3}{2}} \\...\\

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3 years ago
Using the Pythagorean theorem what is the distance between (5,-3) and (9,1)
polet [3.4K]

Step-by-step explanation:

Distance between (5,-3) and (9,1)=√(9-5)^2+(1-(-3))^2

=√4^2+4^2

=√16+16

=√32 units

It's not possible to calculate the distance between these points by pythagoras theorem .We can easily calculate it by distance formula I.e.√(x2-x1)^2+(y2-y2)^2

7 0
3 years ago
This is easy but i’m just dumb. help :))
Lady_Fox [76]

Answer:

I don't know what is in the drop down question, but here are the answers for the others:

1. Triangle possible

2. Triangle possible

3. Triangle possible

4. Triangle not possible

Angles need to add up to 180.

The 2 smallest sides have to be greater summed up than the 3rd side.

Hope this helps!

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5 0
3 years ago
A store sold a total of 21,650 balls. it sold 11,795 baseballs. it sold 4150 fewer basketball than baseballs. the rest of the ba
ivann1987 [24]
Total:21650
-(11,795+4150)
ANSWER^
7 0
3 years ago
Read 2 more answers
Suppose that the lifetime of tv tubes are normally distributed with a standard deviation of 1.1 years. Suppose that exactly 20%
IrinaK [193]

Answer:

4.924 years

Step-by-step explanation:

Lets denote X the lifetime of a tv tube (In years). X has distribution N(\mu, 1.1) , with \mu unknown.

We know that P(X < 4) = 0.2. Using this data, we can find the value of \mu throught standarization.

Lets call Z = \frac{X - \mu}{1.1} the standarization of X. Z has distribution N(0,1), and its cummulative function, \phi is tabulated. The values of \phi can be found in the attached file.

P(X < 4) = P(\frac{X - \mu}{1.1} < \frac{4 - \mu}{1.1}) = P(Z < \frac{4 - \mu}{1.1}) = \phi(\frac{4 - \mu}{1.1}) = 0.2

The value q such that \phi (q) = 0.2 doesnt appear on the table. We can find it by using the symmetry of the normal density function. The opposite of q, -q must verify that \phi(-q) = 0.8 , hence -q must be equal to 0.84. Thus, q = -0.84

But this value of q should match with the number \frac{4 - \mu}{1.1} , so we have

\frac{4- \mu}{1.1} = -0.84

4 - \mu = 1.1 * (-0.84) = -0.924

\mu = 4 - (-0.924) = 4.924

Thus, the expected lifetime of TV tubes is 4.924 years.

I hope this works for you!

Download pdf
7 0
4 years ago
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