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3 years ago

7

I need some more help, I will mark brainliest

1 answer:

Alexus [3.1K]3 years ago

6 0

Download photo math, it helps quicker! step by step.

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What is the lim (1-cos theta)/(2sin^2 theta) as theta approahes 0?

Sergio039 [100]

$\displaystyle
\lim_{\theta\to 0}\dfrac{1-\cos \theta}{2\sin ^2\theta}=\\\\
\lim_{\theta\to 0}\dfrac{(1-\cos \theta)(1+\cos \theta)}{2\sin ^2\theta(1+\cos \theta)}=\\\\
\lim_{\theta\to 0}\dfrac{1-\cos^2 \theta}{2\sin ^2\theta+2\sin^2 \theta\cos \theta}=\\\\
\lim_{\theta\to 0}\dfrac{\sin^2 \theta}{2\sin ^2\theta+2\sin^2 \theta\cos \theta}=\\\\
\lim_{\theta\to 0}\dfrac{1}{2+2\cos \theta}=\\\\
\dfrac{1}{2+2\cdot1}=\\\\
\dfrac{1}{4}
$

4 0

4 years ago

Can they be written as a fraction and if so why

Kruka [31]

The first one can be written as a fraction because it is a repeating decimal.

The second one can be written as a fraction because it is a repeating decimal.

The third one can not be written as a fraction since it is nether terminating nor repeating.

The last one can be written as a fraction since it is a terminating decimal.

4 0

3 years ago

Read 2 more answers

What is the value of 1/6 + 1/12 + 2/6

Elena L [17]

Answer:

7/12

Step-by-step explanation:

1/6 +1/12+2/6

=1×2/6×2 +1/12+2×2/6×2

=2/12+1/12+4/12

final answer is

= 7/12

6 0

3 years ago

Read 2 more answers

A Bernoulli differential equation is one of the form dxdy+P(x)y=Q(x)yn Observe that, if n=0 or 1, the Bernoulli equation is line

aleksandr82 [10.1K]

It's unclear whether the ODE is

$xy'+y=4xy^2$

or

$xy+y'=4xy^2$

If the first case, then divide through both sides by $y^2$ to get

$xy^{-2}y'+y^{-1}=4x$

then substitute $z=y^{-1}$ , so that $z'=-y^{-2}y'$ . Then

$-xz'+z=4x\implies-\dfrac1xz'+\dfrac1{x^2}z=\left(-\dfrac1xz\right)'=\dfrac4x$

$\implies-\dfrac1xz=\displaystyle\int\frac4x\,\mathrm dx$

$\implies z=-4x\ln|x|+Cx$

$\implies\boxed{y=\dfrac1{Cx-4x\ln|x|}}$

If the second, then dividing through by $y^2$ gives

$xy^{-1}+y^{-2}y'=4x$

The same substitution as before gives

$xz-z'=4x\implies e^{-x^2/2}z'-xe^{-x^2/2}z=\left(e^{-x^2/2}z\right)'=-4xe^{-x^2/2}$

$\implies e^{-x^2/2}z=\displaystyle-4\int xe^{-x^2/2}\,\mathrm dx$

$\implies z=4+Ce^{x^2/2}$

$\implies\boxed{y=\dfrac1{4+Ce^{x^2/2}}}$

5 0

3 years ago

Graph the line with slope - 3/4 passing through point (4,-5)

Arlecino [84]

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

The equation of the line in point slope form is equal to

$y-y1=m(x-x1)$

we have

$m=-\frac{3}{4}$

$point\ (4,-5)$

substitute

$y+5=-\frac{3}{4}(x-4)$

Convert to slope intercept form

$y=mx+b$

isolate the variable y

$y+5=-\frac{3}{4}x+3$

$y=-\frac{3}{4}x+3-5$

$y=-\frac{3}{4}x-2$

<u><em>Find the intercepts</em></u>

<em>Find the y-intercept</em> (value of y when the value of x is equal to zero)

For x=0

$y=-\frac{3}{4}(0)-2=-2$

The y-intercept is (0,-2)

<em>Find the x-intercept</em> (value of x when the value of y is equal to zero)

For y=0

$0=-\frac{3}{4}x-2$

$x=-\frac{8}{3}=-2.667$

The x-intercept is (-2.667,0)

To graph the line plot the intercepts and join the points

see the attached figure

3 0

3 years ago