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jeyben [28]
3 years ago
9

How to cross multiply 9/12 =x/100?

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0
The answer is 75. 1. You simplify which is 3/4
2. Change to decimal then number you will get .75 move decimal two to the right to change to number then you will get 75!
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WRITE Which solid has a greater volume: cone with a base radious of 7 centimeters and a height of 28 centimeters or a pyramid Wi
Mumz [18]
The pyramid has a greater volume.
The volume of the cone is 1436.7 ( to 5 sf )
The volume of the pyramid is 1437.3 ( to 5 sf )
Both of them is 1440 when rounded off to 3 sf. However , the volume of the pyramid is greater.
( so sorry I can’t explain well but I hope it helps )
The solution is in the picture:) hope you understand better!! Sorry if It’s confusing

7 0
3 years ago
How do you do this??<br> 14cents/oz = $__/Ib<br> ????????????????
yarga [219]

Answer:

$2.24 / lb

Step-by-step explanation:

$1 = 100 cents

16 oz = 1 lb

14 cents/oz *\frac{1 dollar}{100 cents}*\frac{16oz}{1lb}

Simplified,

\frac{14 *16}{100}

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6 0
3 years ago
Read 2 more answers
Find the value of x.
ella [17]

Answer:

502.4

Step-by-step explanation:

Use tangent because the side you know and the side with x are both legs.  

Do 203/tan(22) and you should get your awnser.  

You devide by 203 because the rule is opposite over ajacent and 203 is the opposite side.

4 0
3 years ago
The volume (in cubic inches) of a shipping box is modeled by V =2x³ -19x² +39x, where x is the length (in inches). Determine the
yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

Therefore;

V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

8 0
3 years ago
Solve x2 – 8x + 15 &lt; 0.
rusak2 [61]
X2 - 8x + 15 = 0
(x  - 3)(x - 5) = 0
critical points are at 3 and 5
8 0
3 years ago
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