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Anettt [7]
3 years ago
8

1.The proportion of all samples randomly drawn from the population whose confidence intervals contain the estimated population p

arameter is the
point estimate.

standard error.

margin of error.

confidence level.

2.A random sample of 1,026 adults in the United States were asked: "Based on what you know about the current Health care system today, what would you like Congress and the President to do during this next year?" Their responses are shown in the table.

Construct a 90% confidence interval for the proportion of all United States adults who think, at the very least, major changes are needed.

3.Based on a random sample of 36 students, it was found that 27 of them have a pet. What is a 95% confidence interval for the proportion of students that have a pet?

0.75 ± 0.25

0.75 ± 0.01

0.75 ± 0.07

0.75 ± 0.19

4.A candy manufacturer claims that no more than 2% of its individually wrapped chocolate candy pieces are missing nuts. A random sample of 100 candy pieces shows that 3 are missing nuts. For α = 0.05, which statement is true?

The candy manufacturer’s claim is likely true, as evidenced by a z-score that is less 1.645.

The candy manufacturer’s claim is likely true, as evidenced by a z-score that is equal to 1.645.

The candy manufacturer’s claim is likely untrue, as evidenced by a z-score that is less than 1.645.

The candy manufacturer’s claim is likely true, as evidenced by a z-score that is greater than 1.645.

5.A survey was conducted to determine the percentage of twelfth grade students who planned to go to college. The results indicated 78% with a margin of error of ±5.

What is meant by ±5?

10% of the population of twelfth grade students was not surveyed.

It is unlikely a sample proportion result of 78% would be obtained unless the true percentage is between 73% and 83%.

For the sample, the percentage of students who plan to go to college was between 73% and 83%

The percentage of the entire population of students who plan to go to college is between 73% and 83%.

6.The CDC reports that 14.9% of all US deaths are attributable to heart disease. In Mississippi, a random sample of 500 death certificates were examined and 124 of them were attributable to heart disease. Construct an 85% confidence Interval for the actual proportion of Mississippi deaths that are from heart disease.

7.A random sample of 1,026 adults in the United States were asked: "Based on what you know about the current Health care system today, what would you like Congress and the President to do during this next year?" Their responses are shown in the table.

Construct a 90% confidence interval for the proportion of all United States adults who think some type of change is needed.

8.A city newspaper selected a simple random sample of 3,800 readers from their list of subscribers. They asked whether the newspaper should increase its local sports coverage.

If 34.5% of the sample wanted more coverage of local sports, what is the 95% confidence interval for the proportion of readers who would like more coverage of local sports?

(0.30, 0.39)

(0.31, 0.38)

(0.32, 0.37)

(0.33, 0.36)

9.A city newspaper selected a simple random sample of 3,800 readers from their list of subscribers. They asked whether the newspaper should increase its local sports coverage.

Based on the 34.5% of readers who wanted more coverage of local sports, the newspaper decides to determine a 99% confidence interval. What is the 99% confidence interval for the proportion of readers who would like more coverage of local sports?

(0.319, 0.371)

(0.325, 0.365)

(0.340, 0.353)

None of the above
Mathematics
1 answer:
Tomtit [17]3 years ago
3 0

Answer:

1) confidence level

3) 0.75 + - 0.25

4) The candy manufacturer’s claim is likely true, as evidenced by a z-score that is less 1.645.

7) 0.87+-1.645\sqrt{\frac{0.87(1-0.87)}{1026} }

9) (0.33,0.36)

Step-by-step explanation:

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