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GrogVix [38]
4 years ago
9

The scores of a given test were normally distributed

Mathematics
1 answer:
julsineya [31]4 years ago
5 0

Answer:

The standard deviation is 6

Step-by-step explanation:

The scores of a given test were normally distributed  with a mean of 82.

\mu = 82

James received a 67 with a z-score of  -2.5

Z score = -2.5

\bar{x}=67

Formula :Z=\frac{x-\mu}{\sigma}

-2.5=\frac{67-82}{\sigma}

\sigma = \frac{67-82}{-2.5}

\sigma =6

Hence The standard deviation is 6

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I WILL GIVE BRAINLIEST The toll on a bridge is $1.00 for cars and $2.50 for trucks. In one hour, a tollbooth operator collects a
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3 years ago
Two Fifths of the vegetables in Priya's garden are tomatoes.
IgorLugansk [536]
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2) x Vegetables?
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3 years ago
Simplify completely..........​
vitfil [10]

Answer:

\frac{x}{x-1}

Step-by-step explanation:

\frac{3x^2 - 1}{x^2 - 1} - \frac{2x + 1}{x + 1}                                          [ \ x^ 2- 1 = (x-1)(x + 1) \ ]

= \frac{3x^2 - 1}{(x-1)(x  + 1 )} - \frac{2x + 1}{x + 1}\\\\=\frac{(3x^2 - 1)-(2x + 1)(x-1)}{(x + 1)(x-1)}                        [\ Taking \ LCM \  ]

= \frac{(3x^2 - 1)- (2x^2 - 2x + x - 1)}{(x+1)(x-1)}\\\\=\frac{3x^2 - 1 - 2x^2 + x + 1 }{(x+1)(x-1)}\\\\=\frac{x^2 +x}{(x+1)(x-1)}\\\\=\frac{x(x+1)}{(x+1)(x-1)}\\\\=\frac{x}{x-1}

<em><u>Finding LCM :</u></em>

Example :

                 \frac{1}{6} + \frac{1}{3}

6 = 2  x   3

3 = 1   x   3

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[ To make the denominators same : the second fraction is multiplied and divided by 2 ]

Similarly :

 (x^2 - 1 ) = (x -1)(x+1)\\\\(x + 1)  = 1 \times (x + 1)

Same rule we applied : multiplied the numerator and denominator of the second term with ( x - 1 )

Therefore the second term becomes ,

                                       \frac{2x + 1}{x + 1} = \frac{(2x + 1)(x - 1)}{(x + 1)( x - 1)}

7 0
3 years ago
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