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Tom [10]
2 years ago
8

Someone help pls :) tyyyy

Mathematics
1 answer:
Andrews [41]2 years ago
8 0

Answer:

OPTION B

Step-by-step explanation:

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Y=x(x−2)^3 identify the zeros and their multiplicities.
lawyer [7]
  • The zeros of the function are 0 and 2
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<h3>Zeros and multiplicities of functions</h3>

Given the function y=x(x-2)^3

The zeros of the function is at the point where y = 0

x(x-2)^3 =0\\x = 0\\(x-2)^3=0\\x-2=0\\x=2

Hence the zeros of the function are 0 and 2

The multiplicity is the power to which the factors are raised. The multiplicities of the function are 1 and 3.

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30 points! Find the four arithmetic means between -17 and 32.
bearhunter [10]

Answer: - 7.2 , 2.6 , 12.4 and 22.2

Step-by-step explanation:

Let the arithmetic means be p , q , r ,s , therefore , the sequence becomes:

-17 , p , q , r , s , 32

The first term (a ) = -17

Last term (L) = 32

common difference (d) = ?

number of terms (n ) = 6

We will use the formula for calculating the last term to find the common difference. That  is

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Substituting the values , we have

32 = -17 + (6-1) d

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32 + 17 = 5d

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Therefore: d = 9.8

We can therefore find the values of p , q , r , and s

p is the second term , that is

p = a + d

p = -17 + 9.8

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q = a + 2d

q = - 17 + 19.6

q = 2.6

r = a + 3d

r = - 17 + 29.4

r = 12.4

s = a + 4d

s = - 17 + 39.2

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