Answer:
^speed, distance, and time^
my answer lies in paper
hope undertand
For the answer to the question above, to solve these questions, use this formula: X3= F(X1-X2) Y3= F(Y1-Y2)
Where X3 is the X value in the coordinate your solving for, F is the fraction,
X1 is the first X and X
2 is the second X Plug in your numbers to fit this: X3= 1/4 x (0--2) Y3= 1/4 x (4- -3) By solving you get: (-.5, 1.75)
Well, 6 / 3 is a solid 2.
So, 1 is less than 6/3
or
1 < 6/3
Hope this helped! ☺♥
Since the two equations equal y, set them equal to each other.
x-1=-2x+5
From there, solve for x.
First get x on one side, by using the addition property of equality.
x-1=-2x+5
3x-1=5
Isolate x by adding 1.
3x=6
Lastly get x all by itself by dividing each side by 3.
x=2
You can now substitute your x-value, 2, into one of the equations (or both, if you wish; either one will result in the same answer.)
y=x-1
y=2-1
y=1
OR
y=-2x+5
y=-2(2)+5
y=-4+5
y=1
Final answer:
x=2 and y=1
Any questions or anything you would like me to clarify, feel free to ask :)
Answer: B or D
Step-by-step explanation:
