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Artemon [7]
3 years ago
5

Lines a and b are parallel. The slope of line b is 1/3 . What is the slope of line a?

Mathematics
1 answer:
lesya692 [45]3 years ago
8 0

Answer:

1/3

Step-by-step explanation:

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WILL MARK BRAINLIEST
kherson [118]

Answer

g(x) = x^3 − x^2 − 4x + 4

End behavior- Falls to the left rises to the right

y intercept-(0, 4)

Zeros- (1,-2,2)

g(x) = x^3 + 2x^2 − 9x − 18

End behavior- Falls to the left rises on the right

y intercept- (0,-18)

Zeros- (-2,-3,3)

g(x) = x^3 − 3x^2 − 4x + 12

End behavior-Falls to the left rises to the right

y intercept-(0,12)

Zeros- (3,-2,2)

g(x) = x^3 + 2x^2 − 25x − 50

End behavior- falls to the left rises to the right

y intercept(0,-50)

Zeros- (-2,-5,5)

g(x) = 2x^3 + 14x^2 − 2x − 14

End behavior- falls to the left rises to the right

y intercept-(0,-14)

Zeros- (-7,-1,1)

Step-by-step explanation:

~Plz tap the crown~

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6 0
3 years ago
What is the distance between the points plotted below? If necessary, round your answer to two decimal places.
34kurt
(-1,1) (6,9)
distance = root (x1-x2)²+(y1-y2)²
so root (-1-6)²+(1-9)²= root 113 or 10.6 ≈11
the answer is B. 11.18 units
8 0
3 years ago
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the diagram shows what tina had left from a yard of fabric. she now uses 2/3 yards of fabric for a project.how much of the origi
kap26 [50]
Cant see the diagram
4 0
3 years ago
Express each of the following quadratic functions in the form of f(x) = a (x - h)²+ k.Then,state the minimum or maximum value,ax
Ivan

Given:

The function is:

f(x)=-2x^2+7x+4

To find:

Express the quadratic equation in the form of f(x)=a(x-h)^2+k, then state the minimum or maximum value,axis of symmetry and minimum or maximum point.

Solution:

The vertex form of a quadratic function is:

f(x)=a(x-h)^2+k              ...(i)

Where, a is a constant, (h,k) is the vertex and x=h is the axis of symmetry.

We have,

f(x)=-2x^2+7x+4

It can be written as:

f(x)=-2\left(x^2-3.5x\right)+4

Adding and subtracting square of half of coefficient of x inside the parenthesis, we get

f(x)=-2\left(x^2-3.5x+(\dfrac{3.5}{2})^2-(\dfrac{3.5}{2})^2\right)+4

f(x)=-2\left(x^2-3.5x+(1.75)^2\right)-2\left(-(1.75)^2\right)+4

f(x)=-2\left(x-1.75\right)^2+2(3.0625)+4

f(x)=-2\left(x-1.75\right)^2+6.125+4

f(x)=-2\left(x-1.75\right)^2+10.125                ...(ii)

On comparing (i) and (ii), we get

a=-2,h=1.75,k=10.125

Here, a is negative, the given function represents a downward parabola and its vertex is the point of maxima.

Maximum value = 10.125

Axis of symmetry : x=1.75

Maximum point = (1.75,10.125)

Therefore, the vertex form of the given function is f(x)=-2\left(x-1.75\right)^2+10.125, the maximum value is 10.125, the axis of symmetry is x=1.75 and the maximum point is (1.75,10.125).

8 0
3 years ago
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