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2 years ago

Which kind of ethical issue is unique to the healthcare industry? financial end-of-life employee-relations safety

Mathematics

2 answers:

andrezito [222]2 years ago

7 0

Answer:

Step-by-step explanation:

Alex73 [517]2 years ago

6 0

Answer:

Step-by-step explanation:

end of life

edge 2020

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Use the Shell Method to find the volume of the solid obtained by rotating region under the graph of f(x)=x^2+2 for 0≤x≤5 about x

Irina18 [472]

For each x in the interval 0 ≤ x ≤ 5, the shell at that point has

• radius = 5 - x, which is the distance from x to x = 5

• height = x ² + 2

• thickness = dx

and hence contributes a volume of 2π (5 - x) (x ² + 2) dx.

Taking infinitely many of these shells and summing their volumes (i.e. integrating) gives the volume of the region:

$\displaystyle 2\pi \int_0^5 (5-x)(x^2+2)\,\mathrm dx=2\pi\int_0^5 (10-2x+5x^2-x^3)\,\mathrm dx=\boxed{\frac{925\pi}6}$

4 0

2 years ago

Let f(x)=3x + 5 and g(x) = 3x2 - x - 10. Find (f/g)(x) and state it’s domain

koban [17]

Answer:

9x²-3x-25, Domain is all real numbers

Step-by-step explanation:

f(g(x)) = 3(3x²-x-10)+5

= 9x²-3x-30+5

= 9x²-3x-25

Domain is all real numbers

5 0

2 years ago

Find The surface area of the cylinder. round your answer to the nearest tenth

trasher [3.6K]

Answer:

791.7

.......

........................

6 0

2 years ago

baherus [9]

Answer: see proof below

Step-by-step explanation:

Given: cos 330 = $\frac{\sqrt3}{2}$

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

$\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}$

Proof LHS → RHS:

LHS cos 165

Double-Angle: cos (2 · 165) = 2 cos² 165 - 1

⇒ cos 330 = 2 cos² 165 - 1

⇒ 2 cos² 165 = cos 330 + 1

Given: $2 \cos^2 165 = \dfrac{\sqrt3}{2} + 1$

$\rightarrow 2 \cos^2 165 = \dfrac{\sqrt3}{2} + \dfrac{2}{2}$

Divide by 2: $\cos^2 165 = \dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \dfrac{2\sqrt3+4}{8}$

Square root: $\sqrt{\cos^2 165} = \sqrt{\dfrac{4+2\sqrt3}{8}}$

Scratchwork: $\cos^2 165 = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2$

$\rightarrow \cos 165 = \pm \dfrac{\sqrt3+1}{2\sqrt2}$

Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

$\rightarrow \cos 165 = - \dfrac{\sqrt3+1}{2\sqrt2}$

LHS = RHS $\checkmark$

4 0

3 years ago

Can someone PLEASE help me out w this?!?!?????

sasho [114]

Hi!

Here's your answer:

x=3 and y=0

I hope this helps!

Feel free to mark brailiest!

5 0

2 years ago