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3 years ago

6

Select all of the following that are ordered pairs of the given function f(x)=3-2x

1 answer:

Alona [7]3 years ago

7 0

What are the following?

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What is the final amount if 558 is decreased by 3% followed by a further 6% increase?

Leno4ka [110]

Answer:

604.58

Step-by-step explanation:

hegarty says its 604.58

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2 years ago

Perform the following calculations without rewriting the numbers in decimal form.

RSB [31]

Answer:

Answer will be $140\times 10^{13}$

Step-by-step explanation:

We have to perform the calculation $(1.42\times 10^{15}-2\times 10^{13})$ without changing into decimal

$1.42\times 10^{15}$ can be written as $142\times 10^{13}$

So $1.42\times 10^{15}-2\times 10^{13}=(142\times 10^{13}-2\times 10^{13})$

Now taking $10^{13}$ common

$10^{13}(142-23)=140\times 10^{13}$

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3 years ago

A line has a slope of 8 and a y -intercept of 5. What is its equation in slope -intercept form? Write your answer using integers

Dahasolnce [82]

Answer:

Step-by-step explanation:it’s abc

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2 years ago

What is 0.000099 in scientific notation??

Lerok [7]

The answer would be 99, because because if you remove the decimals and the 0's you get 99.

7 0

3 years ago

A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte

puteri [66]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

$\angle SPR=7.1^0$ =Angle subtended by the statue to where you are standing.

$\angle x$ = $\angleRPQ$ which is unknown.

Let us begin solving now. The first step is to find the angle $\angle x$ which can be found by using the following trigonometric ratio in $\Delta PQR$ :

$tan(x)=\frac{RQ}{PQ}=\frac{21}{57}$

Which gives x to be:

$x=tan^{-1} (\frac{21}{57})\approx 20.22^{0}$

Now, we know that $\angle x$ and $\angle SPR$ will get added to give us the complete angle $\angle SPQ$ in the right triangle $\Delta PQS$ .

We can again use the tan trigonometric ratio in $\Delta PQS$ to solve for the height of the statue, h.

This can be done as:

$tan(\angle SPQ)=\frac{SQ}{PQ}$

$tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}$

$tan(27.32^0)=\frac{h+21}{57}$

$\therefore h+21=57\times tan(27.32^0)$

$h\approx8.45 feet$

Thus, the height of the statue is approximately, 8.45 feet.

5 0

3 years ago

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