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Tpy6a [65]
3 years ago
6

Select all of the following that are ordered pairs of the given function f(x)=3-2x

Mathematics
1 answer:
Alona [7]3 years ago
7 0
What are the following?
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Solve the Quadratic
MariettaO [177]

Answer:

solution 1: 3

solution 2: 9

Step-by-step explanation:

1) solution 1 + solution 2 = 12;

2) solution 1 * solution 2 = 27;

3) only 3 and 9 meet these two requirements.

note. this equation can be resolved using another way.

4 0
3 years ago
What is the difference when the product of 0.3 and 0.4 is subtracted from the sum of 0.3 and 0.4?​
Rudik [331]

Answer:

0.58

Step-by-step explanation:

The first approach to solving the question above is to find the product of 0.3 and 0.4 thus:

0.3 \times 0.4 = 0.12

Next step is to find the sum of 0.3 and 0.4 thus:

0.3 + 0.4 = 0.7

The final step is to find the difference between the two results. Thus:

0.7 - 0.12 = 0.58

Therefore, the product of 0.3 and 0.4 subtracted from the sum of 0.3 and 0.4 is 0.58

7 0
3 years ago
The mpg (miles per gallon for a certain compact car is normally distributed with a mean of 31 and a standard deviation of 0.8. w
lesantik [10]
For this Q:

mean=31
st.dev.=0.8
x=32

Calculate z-score:
z=(x-m)/s = (32-31)/0.8=1.25

This z-score value corresponding to the probability of 0.8944

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6 0
3 years ago
Is 1/3 greater than 1/2???????????
CaHeK987 [17]

Answer:

no

Step-by-step explanation:

half is bigger then 1/3 think of it like this split a pizza into 2 pieces and the other into 3 take one out of both which is bigger if that helps

8 0
3 years ago
A boat is 400 feet away from one dock and 500 feet away from the another dock. the angle between the paths is 45°. what is the a
FinnZ [79.3K]

Answer:

  • The approximate distance between the docks is 357 feet

Step-by-step explanation:

Let the distance between docks be d.

This is the opposite side to 45° angle of triangle with other sides 400 ft and 500 ft.

Use the law of cosines to find the value of d:

  • d = \sqrt{400^2+500^2-2*400*500*cos45} =357 (rounded)
8 0
2 years ago
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