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beks73 [17]
2 years ago
12

Solve this inequality for x. -46-8x>22

Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
7 0

Answer:

x < -8.5

Step-by-step explanation:

-46-8x>22

add 46 to both sides

-8x >68

divide both sides by -8

x < -8.5

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Need help with understanding table of ordered pairs , I have two left and that's basically all.
azamat

Answer:

A

Step-by-step explanation:

The easiest way to figure this out is to substitute in the variables. So for a, 2=-5+7 is correct, and 7=0+7 is correct as well. If you were to look at the other answers, you would see that the equation would not match up. Hope this helps!

8 0
3 years ago
Jim drove 204 miles in 4 hours. If he can keep the same pace how long will it take him to drive 918 miles
SSSSS [86.1K]
18 hours.

Proportions and stuff.

\frac{204}{4} = \frac{918}{x}

Cross multiply,

204x = 918 * 4

204x = 3672
/204      /204
x = 18

18 hours.
6 0
3 years ago
In ⊙P, QR≅ST. Which statement must be true? Select all that apply.
den301095 [7]

The true statement about the circle with center P is that triangles QRP and STP are congruent, and the length of the minor arc is 11/20π

<h3>The circle with center P</h3>

Given that the circle has a center P

It means that lengths PQ, PR, PS and PT

From the question, we understand that QR = ST.

This implies that triangles QRP and STP are congruent.

i.e.  △QRP ≅ △STP is true

<h3>The length of the minor arc</h3>

The given parameters are:

Angle, Ф = 99

Radius, r = 1

The length of the arc is:

L = Ф/360 * 2πr

So, we have:

L = 99/360 * 2π * 1

Evaluate

L = 198/360π

Divide

L = 11/20π

Hence, the length of the minor arc is 11/20π

Read more about circle and arcs at:

brainly.com/question/3652658

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5 0
2 years ago
HELP DUE IN 10 MINS!!
fredd [130]

Answer:

  • D. No, they are not similar.

Step-by-step explanation:

<u>Check the ratio of the two given sides:</u>

  • MV/VT = 21/49 = 3/7
  • LV/VU = 8/28 = 2/7

Ratios are different so the triangles are not similar

Correct choice is D

5 0
3 years ago
A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation A=45e^{-0.05t}.

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate A=15 and solve for t as:

15=45e^{-0.05t}

\frac{15}{45}=\frac{45e^{-0.05t}}{45}

\frac{1}{3}=e^{-0.05t}

Now we will switch sides:

e^{-0.05t}=\frac{1}{3}

Let us take natural log on both sides of equation.

\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})

-0.05t\cdot (1)=\text{ln}(\frac{1}{3})

-0.05t=\text{ln}(\frac{1}{3})

t=\frac{\text{ln}(\frac{1}{3})}{-0.05}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}

t=-\text{ln}(\frac{1}{3})\cdot 20

t=-(\text{ln}(1)-\text{ln}(3))\cdot 20

t=-(0-\text{ln}(3))\cdot 20

t=20\text{ln}(3)

Therefore, it will take 20\text{ln}(3) years for area of the glacier to decrease to 15 square kilo-meters.

6 0
3 years ago
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